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andreyandreev [35.5K]
2 years ago
14

Fill in the blank to make the following true. 2 ** 3 =

Computers and Technology
2 answers:
avanturin [10]2 years ago
7 0

Answer:

2 ** 3 = 8

Explanation:

Alona [7]2 years ago
6 0

Answer:

8

Explanation:

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In networking, bandwidth is the volume of computer data carried via a conductor in a period of time. Which one of these could be
masya89 [10]

Answer:

The answer is "Fiber Optic Cable".

Explanation:

In the given question options are defined, but in these options, there is some error.

The optical fiber cable is also known as internet wiring, which includes fiber strands inside an isolated housing. It is used to transferring data at a very high speed. This cable is developed for long-range data networking, high-performance connectivity, and multimedia, and other choices are wrong that can be described as follows:

  • A modem is used to transmits data over a network, that's why it is wrong.
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3 years ago
What is the body of scientific knowledge based on?
ANTONII [103]
It depend on all such as guess ,observation ,hypothesis and etc
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3 years ago
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When selecting a color scheme for a project which two things should you consider?
Vsevolod [243]

colorfulness and depending on your teacher pick colors that will go together on the project

6 0
3 years ago
A computer on a network that is not the server​
katrin [286]

Answer:

A peer-to-peer network is one in which two or more PCs share files and access to devices such as printers without requiring a separate server computer or server software. ... A P2P network can be an ad hoc connection—a couple of computers connected via a Universal Serial Bus to transfer files.

5 0
2 years ago
) Consider a router that interconnects four subnets: Subnet 1, Subnet 2, Subnet 3 and Subnet 4. Suppose all of the interfaces in
erik [133]

Answer:

Check the explanation

Explanation:

223.1.17/24 indicates that out of 32-bits of IP address 24 bits have been assigned as subnet part and 8 bits for host id.

The binary representation of 223.1.17 is 11011111 00000001 00010001 00000000

Given that, subnet 1 has 63 interfaces. To represent 63 interfaces, we need 6 bits (64 = 26)

So its addresses can be from 223.1.17.0/26 to 223.1.17.62/26

Subnet 2 has 95 interfaces. 95 interfaces can be accommodated using 7 bits up to 127 host addresses can represented using 7 bits (127 = 27)

and hence, the addresses may be from 223.1.17.63/25 to 223.1.17.157/25

Subnet 3 has 16 interfaces. 4 bits are needed for 16 interfaces (16 = 24)

So the network addresses may range from 223.1.17.158/28 to 223.1.17.173/28

4 0
3 years ago
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