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nataly862011 [7]
2 years ago
12

A sample of 8.00 g of Mg(OH)2 is added to 24.2 mL of 0.205 M HNO3. How many moles of Mg(OH)2 our present after the reaction is c

omplete?
Chemistry
1 answer:
kogti [31]2 years ago
6 0

The amount of Mg(OH)2  present after the reaction is complete is 0.136 moles of Mg(OH)2.

The equation of the reaction is;

2HNO3(aq) + Mg(OH)2(aq) -------> Mg(NO3)2(aq) + 2H2O(l)

Number of moles of Mg(OH)2 = 8.00 g/58 g/mol = 0.138 moles

Number of moles of HNO3 = 0.205 M × 24.2 mL/1000 = 0.00496 moles

Given that;

2 moles of HNO3 reacts with 1 mole of Mg(OH)2

0.00496 moles of HNO3 reacts with 0.00496 moles ×  1 mole /2 moles = 0.00248 moles of Mg(OH)2

Hence, Mg(OH)2 is the reactant in excess.

The amount of Mg(OH)2 remaining = Amount present - Amount reacted

Hence; 0.138 moles - 0.00248 moles = 0.136 moles of Mg(OH)2

Learn more: brainly.com/question/9743981

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Which factor MOST directly affects the flow of ocean currents?w of ocean currents?
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B)  differences in temperature

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10. A 38.0-g sample of NaOH is dissolved in water, and the solution is diluted to give a final
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Answer:

B.0.558M

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M=n/L

n=m/Mm

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8 0
3 years ago
A 1dm3 solution was made by mixing 0.0040 mol of HCl(aq) and 0.0025 mol of NaOH(aq). What was the pH of the resulting solution?
kicyunya [14]

The pH of the resulting solution is 2.82.

<h3>What is pH ?</h3>

pH is the measure of acidity and alkalinity of a solution , It has a range of 1 to 14.

HCl          +                   NaOH      →         NaCl       +         H₂O

0.0040                         .0025                 0                       0

0.0040 -0.0025             0                   0.0025          0.0025

Moles of HCl = 0.0015

As 0.0025 moles of NaOH reacts with 0.0025 moles of HCl leaving behind 0.0015 moles of HCl

Concentration of HCl = 0.0015/ 1 = 0.0015 M

[ H⁺] = 0.0015 M

pH = -log [ H⁺]

pH = -log [ 0.0015]

pH = 2.82

Therefore the pH of the resulting solution is 2.82.

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7 0
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