<u>Answer:</u> The pH of the solution is 9.71
<u>Explanation:</u>
1 mole of NaOH produces 1 mole of sodium ions and 1 mole of hydroxide ions.
We are given:
pOH of the solution = 7.2
To calculate the pH of the solution, we need to determine pOH of the solution. To calculate pOh of the solution, we use the equation:
![pOH=-\log[OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%5BOH%5E-%5D)
We are given:
![[OH^-]=5.09\times 10^{-5}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D5.09%5Ctimes%2010%5E%7B-5%7DM)
Putting values in above equation, we get:

To calculate pH of the solution, we use the equation:

Hence, the pH of the solution is 9.71
Answer:
Mg is oxidized and Pb is the oxidizing agent
Explanation:
Answer is a
bacteria doesn't have any cellular function in the cell.
Answer: 0.002 M
Explanation:
The balanced chemical equation for ionization of
in water is:

According to stoichiometry :
1 mole of
ionizes to give =2 mole of
ions
0.001 mole of
ionizes to give =
mole of
ions
Thus
of a solution of 0.001 M aqueous sulfuric acid is 0.002 M