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krek1111 [17]
3 years ago
7

Carbon 14 has a half-life of 5730 years. A geologist has dated a fossil sample, at roughly 28650 years. How much carbon 14 remai

ns in the fossil sample?
the carbon 14 has undergone 5 half-lives.
Chemistry
1 answer:
IgorC [24]3 years ago
7 0
<h3>Answer </h3>

After another 5730 years ( three half lives or 17190 years) 17.5 /2 = 8.75mg decays and 8.75g remains left. after three half lives or 17190 years, 8.75 g of C-14 will be

Explanation:

hope this help

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4 0
3 years ago
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Methane CH4 (g) reacts with oxygen gas to produce carbon dioxide and water. ____________________________________________________
nordsb [41]

<u>Answer:</u> The chemical equations are written below.

<u>Explanation:</u>

<u>For a:</u> Methane reacts with oxygen gas to produce carbon dioxide and water.

Combustion reaction is defined as the reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide and water

The chemical equation for the combustion of methane follows:

CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)

  • <u>For b:</u> Butane reacts with oxygen gas to produce carbon dioxide and water.

This is also an example of combustion reaction.

The chemical equation for the combustion of butane follows:

2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

  • <u>For c:</u> An aqueous solution of sulfuric acid reacts with aqueous potassium hydroxide to produce potassium sulfate and water.

When an acid reacts with a base, it leads to the formation of salt and water. This reaction is known as neutralization reaction

The chemical equation for the reaction of potassium hydroxide and sulfuric acid follows:

H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O

Hence, the chemical equations are written above.

4 0
4 years ago
Calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxid
kiruha [24]

Answer:

-471 Kj/mole acrylic acid

Explanation:

THIS IS THE COMPLETE QUESTION BELOW;

There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In the first step, calcium carbide and water react to form acetylene and calcium hydroxide: CaC (s) + 2 H2O(g) - CH (9) + Ca(OH),(s) AH -414. kJ In the second step, acetylene, carbon dioxide and water react to form acrylic acid: 6 C H (9) + 3 CO2(9) + 4H2O(g) - SCH,CHCO,H) AH-132. kJ Calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reactions. Round your answer to the nearest kJ. x 5 ?

The two equations from the reaction can be written as;

a)CaC₂(s) + 2H₂O(l) ------->C₂H₂(g) + CaOH₂(s)

Δ H= -414Kj ........................ equation (a)

b)6C₂H₂(g) +3CO₂(g)+4H₂O(g) -------> 5CH₂CHCO₂H(g) Δ H= 132Kj ...................... equation (b)

In equation (b)acrylic acid was produced by the reaction between Acetylene carbon dioxide and water

Then we can multiply equation(a) by factor of 6 and the ΔH Then we have (6× -414Kj)= ΔH= -2484Kj.

6CaC₂(s) + 12H₂O(l) ------->6C₂H₂(g) + 6CaOH₂(s)

Δ H= -2484Kj.................. equation (c)

6C₂H₂(g) +3CO₂(g)+4H₂O(g) -------> 5CH₂CHCO₂H(g) Δ H= 132Kj

Then add equation (c) and equation(b) then we have

6CaC₂(s) + 16H₂O(l)+3CO₂(g)------> 5CH₂CHCO₂H(g) + 6CaOH₂(s) ΔH= -2352Kj

ΔH(net)= -2352Kj/5moles

=-471Kj/mole

therefore, net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reactions. Round your answer to the nearest kJ. x 5 ? is -471Kj/mole acrylic acid

6 0
3 years ago
How many total carbon atoms are in the structure 2 methyl, 3, 4 diethyl decane?
makvit [3.9K]

Answer:B

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6 0
3 years ago
A 55.9 g sample of water at 99.2 °c is placed in a constant pressure calorimeter. then, 23.9 g of zinc metal at 21.1 °c is added
Veronika [31]
<span>Heat released by the water: mass * specific heat * ΔT

Heat released by the water = 55.9 g * 1 cal / (°C g) * (99.2 - 96.9 )°C

Heat absorbed by the zinc metal = mass * specifi heat * ΔT

Heat absorbed by the zinc metal =  23.9 g * Cp * (96.9 - 21.1) °C

Heat absorbed by zinc metal = heat released by water

=> 23.9 * Cp * 75.8 = 55.9 * 1 * 2.3

=> Cp = 128.57 / 1811.62 = 0.0071 cal / (g°C)

Answer: 0.0071 cal / (g°C)
</span>
4 0
3 years ago
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