Answer:
Confidence Interval - 2.290 < S < 2.965
Step-by-step explanation:
Complete question
A chocolate chip cookie manufacturing company recorded the number of chocolate chips in a sample of 50 cookies. The mean is 23.33 and the standard deviation is 2.6. Construct a 80% confidence interval estimate of the standard deviation of the numbers of chocolate chips in all such cookies.
Solution
Given
n=50
x=23.33
s=2.6
Alpha = 1-0.80 = 0.20
X^2(a/2,n-1) = X^2(0.10, 49) = 63.17
sqrt(63.17) = 7.948
X^2(1 - a/2,n-1) = X^2(0.90, 49) = 37.69
sqrt(37.69) = 6.139
s*sqrt(n-1) = 18.2
confidence interval:
(18.2/7.948) < S < (18.2/6.139)
2.290 < S < 2.965
Answer:
Idk how to explain but I think its C
Please don't delete my answer unless its wrong to those who love deleteing answers
Step-by-step explanation:
Answer:
213 in base 4 = 124 in base 5
Step-by-step explanation:
First we convert base 4 to base 10
213 in base 4
2*42 + 1*41 + 3*40
32 + 4 + 3
39 in base 10
Now we convert base 10 to base 5
39/5
7/5 r = 4
1 r = 2
124 in base 5
Hence 213 in base 4 = 124 in base 5
Answer:
The length is 10 cm
Step-by-step explanation:
The area is given by length times width
A = l*w
We have an area of 80 cm^2 and a width of 8
80 = l*8
Divide each side by 8
80/8 = 8l/8
10 = l
The length is 10 cm
Isolate the variable by dividing each side by factors that don't contain the variable.
