The simplification of a³ - 1000b³ and 64a³ - 125b³ is (a - 10b) × (a² + 10ab + 100b²) and 4a - 5b) • (16a² + 20ab + 25b²) respectively.
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Simplification</h3>
Question 1: a³ - 1000b³
a³ - b³
= (a-b) × (a² +ab +b²)
- 1000 is the cube of 10
- a³ is the cube of a¹
- b³ is the cube of b¹
So,
(a - 10b) × (a² + 10ab + 100b²)
Question 2: 64a³ - 125b³
a³ - b³
= (a-b) × (a² +ab +b²)
- 64 is the cube of 4
- 125 is the cube of 5
- a³ is the cube of a¹
- b³ is the cube of b¹
So,
(4a - 5b) • (16a² + 20ab + 25b²)
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About 38 cars. 300/8= 37.5 cars. There is no such thing as 0.5 of a car so round up to the nearest whole number.
Answer:
56
Step-by-step explanation:
El problema se puede transcribir en esta ecuación:
2x + x = 168
siendo x las nectarinas
sumas los términos de x:
3x=168
despejas x:
x = 168 ÷ 3
x = 56
Answer:
y= 250( 1-0.21)^x
Step-by-step explanation:
This represents exponential decay
Answer:
x = 14
Step-by-step explanation:
comp = add up to be 90
3x + 14 + 2x + 6 = 90
5x + 20 = 90
5x = 70
x = 14
