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xxTIMURxx [149]
2 years ago
7

When calculating a loan’s effective rate, if the interest compounds every two months, what value of n do you plug into your equa

tion? a. 2 b. 0.167 c. 6 d. 60
Mathematics
2 answers:
olga2289 [7]2 years ago
8 0

The value of n you plug into your equation will be 6. Then the correct option is C.

<h3>What is compound interest?</h3>

Compound interest is the interest on a loan or deposit calculated based on the initial principal and the accumulated interest from the previous period.

When calculating a loan’s effective rate.

If the interest compounds every two months.

Then the value of n you plug into your equation will be

If the interest is compounded every two months, the interest will be applied six times every year.

Because there are 12 months in a year, the value of n that you will plug into your equation is 6, and it will be compounded every two months.

More about the compound interest link is given below.

brainly.com/question/25857212

jeka57 [31]2 years ago
7 0

Answer:

C

Step-by-step explanation:

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At the beginning of a semester an anonymous survey was conducted on students in a statistics class. Two of the questions on the
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a. Chi-square test of independence

Step-by-step explanation:

The chi square statistics is also used to test the hypothesis about the independence of two variables each of which is classified into a number of categories or attributes.

In the given problem the Equal , more or less are the attributes.

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4 0
3 years ago
Aubrey's dinner cost $85. She tips the waitstaff 30%, for excellent service.
Olin [163]
30% is equal to 0.3 (found by dividing the percentage by 100). Then we multiply the cost of dinner, $85, by 0.3 to find an answer of $25.50.

Answer: $25.50
6 0
2 years ago
Given that
VLD [36.1K]

-17/2

Step-by-step explanation:

30-8(8)+4y

30=64+4y

30-64=4y

-34=4y

y= -34/4

y= -17/2

hope it helps!

6 0
3 years ago
) f) 1 + cot²a = cosec²a​
notsponge [240]

Answer:

It is an identity, proved below.

Step-by-step explanation:

I assume you want to prove the identity. There are several ways to prove the identity but here I will prove using one of method.

First, we have to know what cot and cosec are. They both are the reciprocal of sin (cosec) and tan (cot).

\displaystyle \large{\cot x=\frac{1}{\tan x}}\\\displaystyle \large{\csc x=\frac{1}{\sin x}}

csc is mostly written which is cosec, first we have to write in 1/tan and 1/sin form.

\displaystyle \large{1+(\frac{1}{\tan x})^2=(\frac{1}{\sin x})^2}\\\displaystyle \large{1+\frac{1}{\tan^2x}=\frac{1}{\sin^2x}}

Another identity is:

\displaystyle \large{\tan x=\frac{\sin x}{\cos x}}

Therefore:

\displaystyle \large{1+\frac{1}{(\frac{\sin x}{\cos x})^2}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{1}{\frac{\sin^2x}{\cos^2x}}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}

Now this is easier to prove because of same denominator, next step is to multiply 1 by sin^2x with denominator and numerator.

\displaystyle \large{\frac{\sin^2x}{\sin^2x}+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}\\\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}

Another identity:

\displaystyle \large{\sin^2x+\cos^2x=1}

Therefore:

\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}\longrightarrow \boxed{ \frac{1}{\sin^2x}={\frac{1}{\sin^2x}}}

Hence proved, this is proof by using identity helping to find the specific identity.

6 0
3 years ago
-3 × 15v can you answer this
Goryan [66]

Question

-3 × 15v can you answer this


Answer:

<h2>-45v</h2>

Step-by-step explanation:

-3 * 15v =

-45v


6 0
3 years ago
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