Ask question

Ask question

All categories

2 years ago

15

Erik used the Factor Theorem to find the remainder of 2x3-4x2-28x+6 divided by x+3. If he calculated the remainder to be 0, what

does that tell him?

1 answer:

Annette [7]2 years ago

4 0

Step-by-step explanation:

x + 3 = 0

x = - 3

f(x) = 2x³ - 4x² - 28x + 6

f(- 3) = 2(- 3)³ - 4(- 3)² - 28 x (- 3) + 6

= 2 x (- 27) - (4 x 9) + 84 + 6

= - 54 - 36 + 90

= - 90 + 90

= 0

Therefore,

x + 3 is factor of 2x³ - 4x² - 28x + 6

You might be interested in

5 ft 9 ft<br> gft/ 7H-<br> 2 ft<br> 13 ft<br> Surface Area:<br> Volume:

Jet001 [13]

Answer: you like it if I could double the height of your cat food can?” 6 in. 7 in. 15 cm. 30 cm. 13 ft. 6 ft ... 3 ft. 2 ft. 4 ft. 2. 5 m. 8 m. 8 m. Areas of bases. Areas of lateral faces. Exercises 7–9. Lesson Tutorials ... WRAPPING PAPER A cube-shaped gift is.

8 0

3 years ago

What percent of 55 is 34

djyliett [7]

answer

.618 18 repeats

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Here is a list of numbers:<br> 3,16, 7, 19, 1, 12, 3,9,16,12<br> State the median.

fomenos

Answer:

10.5

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

4 0

2 years ago

Which symbol correctly compares these two fractions?<br> 4/7 and 8/16

WITCHER [35]

Answer: 4/7 > 8/16

Step-by-step explanation:

Draw each fraction on a fraction bar (similar to a Hersey's Bar each fraction bar being the same length just broken up differently to represent each fraction) and you will see that 4/7 is bigger than 8/16.

5 0

2 years ago