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IgorLugansk [536]
3 years ago
10

A piece of equipment moves 16.5 yards in 12 minutes. how many feet does it move per minute? round the answer to three decimal pl

aces
Mathematics
1 answer:
Furkat [3]3 years ago
8 0
To solve the feet per minute of the equipment, we must solve the velocity of the the equipment. where velocity is:
V = d / t
where d is the distance traveled
t is the time of travel
V = 16.5 yard / 12 min
V = 1.375 yard / min ( 3 ft / 1 yard )
V = 4.125 ft / min
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Which of the following conjectures is false?<br>Please give a counterexample!<br>Thank youuu
MakcuM [25]

Which of the following conjectures is false?

Solution: The false conjecture is:

J. The sum of two odd numbers is odd

Explanation:

F. The product of two even numbers is even.

For example: Let us take two even numbers 4 and 6.

The product of two even numbers is:

4 \times 6 = 24

Therefore, the product is also even number. Hence the conjecture is true.

G. The sum of two even numbers is even.

For example: Let us take two even numbers 4 and 6.

The sum of two even numbers is:

4+6 = 10

Therefore, the sum is also even number. Hence the conjecture is true.

H. The product of two odd numbers is odd.

For example: Let us take two odd numbers 3 and 5.

The product of two odd numbers is:

3\times5 = 15

Therefore, the product is also odd number. Hence the conjecture is true.

J. The sum of two odd numbers is odd.

For example: Let us take two odd numbers 3 and 5.

The sum of two odd numbers is:

3+5= 8

Therefore, the sum is not an odd number. Hence the conjecture is false.

6 0
3 years ago
An item was originally priced at $6, but you used a coupon and bought it for $4.80. What percent was the coupon you used?
Luden [163]

Answer:

You used 80% I think :)

Step-by-step explanation:

8 0
3 years ago
The state of Colorado has roughly the shape of a rectangle that is 3.8 x 102 miles long and 2.8 x 102 miles high. What is the ap
Illusion [34]
104,185 miles is the area of Colorado
6 0
3 years ago
A game involves correctly choosing the 5 correct numbers from 1 through 18 that are randomly drawn. What is the probability that
bazaltina [42]

Answer:

=\frac{1}{8568}\ = .00011\\\ =\frac{7}{8568}  = .00081

Step-by-step explanation:

5/18\cdot \:4/17\cdot \:3/16\cdot \:2/15\cdot \:1/14=\frac{1}{8568}

4 0
3 years ago
A manufacturer uses production method to produce steel rods. A random sample of 17 steel rods resulted in lengths with a standar
Arisa [49]

Answer:

\chi^2 =\frac{17-1}{12.15} 22.09 =15.87

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates \alpha/2 =0.05 of the area on each tail and we got:

\chi^2_{crit}= 7.962

\chi^2_{crit}=26.296

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is NOT significantly different from 3.5 cm

Confidence level method

We can find the p value like this

p_v =2*P(\chi^2 >15.87)=0.92

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is NOT significantly different from 3.5 cm

Step-by-step explanation:

Data provided

n=17 represent the sample selected

\alpha=0.1 represent the significance

s^2 =4.7^2 =22.09 represent the sample variance

\sigma^2_0 =3.5^2 =12.15 represent the value to check

Null and alternative hypothesis

We want to verify if the new production method has lengths with a standard deviation different from 3.5 cm, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 12.15

Alternative hypothesis: \sigma^2 \neq 12.15

The statistic for this case is given by:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

The degrees of freedom are:

df =n-1= 17-1=16

\chi^2 =\frac{17-1}{12.15} 22.09 =15.87

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates \alpha/2 =0.05 of the area on each tail and we got:

\chi^2_{crit}= 7.962

\chi^2_{crit}=26.296

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is significantly different from 3.5 cm

Confidence level method

We can find the p value like this

p_v =2*P(\chi^2 >15.87)=0.92

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is significantly different from 3.5 cm

7 0
3 years ago
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