Answer:
Option C i.e., Trip criteria is correct
Explanation:
The concept Trip criteria are described that when the allowing requirements for its diagnostic code are reached.
In other words, Trip seems to be a key-on method where all the allowing requirements for such a specific diagnostic display are fulfilled as well as the diagnostic monitoring is powered. It is finished once the ignition switch becomes switched off.
- Option A and Option B are not correct because they are the engines that come under the performance ignition system and they are not related to the following scenario.
- Option D is incorrect because it is the type of data mining that is not related to the scenario.
When we say suburban area, this is the area that is only a part of the city or a region that is distant from the city but not to the point that it becomes rural. So for John, the best way for him to save up in order to acquire a place to stay in the suburbs is to move first to the suburbs and rent a home for a year. This would give John enough time to decide whether he would like the suburban living and to look for a perfect location for his house.
Answer:
True
Explanation:
IPv6 Is a later version of IP addresses, used to solve the problem of the limited number of IPv4 addresses in the network.
Just like IPv4, IPv6 can also is configured to a device statically and dynamically. Dynamic IPv6 configuration could be a stateless autoconfiguration SLAAC, a stateless DHCPV6 or a stateful DHCPV6.
The IPv6 address is configured with a prefix and a prefix length and a EUI generated 64 bit interface or a random interface id by the device.
Answer:
Answer explained below
Explanation:
void bubbleSort(int X[], int Y[], int n)
{
int i, j;
for (i = 0; i < n-1; i++)
// Last i elements are already in place
for (j = 0; j < n-i-1; j++)
if (X[j] > X[j+1])
{
swap(X[j],X[j+1])
swap(Y[j],Y[j+1]);
}
if (X[j] == X[j+1]&&Y[j]<Y[j+1])
{
swap(X[j],X[j+1])
swap(Y[j],Y[j+1]);
}
}
Since the above algorithm contains 2 nested loops over n.
So, it is O(n^2)
Answer:
x_inp = [ '1', '2', '3']
int_val = [ int(a) for a in x_inp ]
print("integer: int_val")
y_inp = [ '1.0', '2.0', '3.0']
flo_val = [ float(a) for a in y_inp ]
print("float: flo_val")
Explanation:
All the items in the arrays x_inp and y_inp are coverted to integer and float data types respectively with the for loop statement, which individually assigns the resolved integer and float values to the memory locations int_val and flo_val respectively.
The output becomes,
integer:
1
2
3
float:
1.0
2.0
3.0
