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algol13
2 years ago
12

_____ means collecting vast amounts of data from a host of websites.

Computers and Technology
2 answers:
xenn [34]2 years ago
8 0

Answer:

D

Explanation:

D. Web Scraping is the answer

Pepsi [2]2 years ago
4 0
D. Web scraping
Explanation: definition “a term for various methods used to collect information from across the internet”
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Which one is not the part of motherboard ?<br>O Registers<br>O<br>Bus<br>O<br>Port<br>O<br>none​
Svetradugi [14.3K]

Answer:

can you expand on your question?

5 0
3 years ago
Which of the following statement about CAD is NOT true A. It increase the productivity of designers B. It uses computer graphics
Sedaia [141]

Answer:

D. All are true.

Explanation:

All the given statements about CAD are true.

5 0
3 years ago
Take the average of some numbers. Show all the numbers that are below average. You can assume that there will not be more than 2
olchik [2.2K]

Here is code in java.

import java.util.*; // import package

class Main //  creating class

{

public static void main (String[] args) // main method

{

Scanner br=new Scanner(System.in); // scanner class for input

       int []a=new int[20]; // declaring array

       int count=0,x,j; // creating variable

       int sum =0;

       System.out.println("Enter a weight (0 to stop):");

       x=br.nextInt(); // taking input

while(x!=0) // iterating over the loop

       {

           a[count] = x;

           count++;

           System.out.println("Enter a weight (0 to stop):");

           x=br.nextInt();

}

       for( j=0;j<count;j++) // iterating over the loop

       {

       sum+=a[j];

       }

       double avg = sum/(double)count;

       System.out.println("The total is: "+sum);

       System.out.println("The average is: "+avg);

       System.out.println("Here are all the numbers less than the average: ");

     for( j=0;j<count;j++) //  // iterating over the loop

       {

           if(a[j]<avg)

           System.out.print(a[j]+" ");

       }

}

}

Explanation:

First create an object of "Scanner" class to read input from the user.

Create an array of size 20, which store the number given by user.Ask user

to give input and keep the count of number in the variable "count". If user

give input 0 then it will stop taking input.And then calculate sum of all the

input.It will calculate average by dividing the sum with count and print it.

It will compare the all elements of array with average value, if the element

is less than average, it will print that element.

Output:

Enter a weight (0 to stop):

1

Enter a weight (0 to stop):

2

Enter a weight (0 to stop):

3

Enter a weight (0 to stop):

4

Enter a weight (0 to stop):

5

Enter a weight (0 to stop):

6

Enter a weight (0 to stop):

7

Enter a weight (0 to stop):

8

Enter a weight (0 to stop):

9

Enter a weight (0 to stop):

10

Enter a weight (0 to stop):

0

The total is: 55

The average is: 5.5

Here are all the numbers less than the average:

1 2 3 4 5

6 0
4 years ago
Write the proghrams for the following:
belka [17]

Answer:

a)

#include <iostream>

using namespace std;

int main() {

   bool a,b,c;

   cin>>a>>b;

   if(a^b)//X-OR operator in C++.

   c=true;

   else

   c=false;

   cout<<c;

return 0;

}

b)

#include <iostream>

using namespace std;

int main() {

   bool a,b,c,d;

   cin>>a>>b>>c;

   if((a^b)^c)//X-OR operator in C++.

   d=true;

   else

   d=false;

   cout<<d;

return 0;

}

Explanation:

The above written programs are in C++.There is an operator (^) called X-OR operator in C++.It returns true if the number of 1's are odd and returns false if the number of 1's are even.

In the if statement I have user X-OR operator(^) to find the result and storing the result in another boolean variable in both the questions.

5 0
4 years ago
Evaluating how current, credible, and unbiased a source is ensures:
Tanya [424]

The answer is

A. your information is more accurate and useful

I hope it helps you. Please mark me brainliest answer.

6 0
3 years ago
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