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3 years ago

What is u? -u+300=200

2 answers:

5 0

To find out u, you can do the following:

1) Subtract 300 from both sides to get:

-u = -100

2) Divide both sides by -1:

Therefore u = 100

Hope this has helped your question.

vodomira [7]3 years ago

4 0

Answer:

100

Step-by-step explanation:

200-300= -100 But the negative of a negative is a positive so the answer is: 100.

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Can anybody help out this math question it’s about graph please

malfutka [58]

Neither one of the slopes are going to be minus. It means you are travelling backwards in time, which is wonderful if you are a sci-fi fan, but not so good if you are Sharon. A and D has Sharon going from 70 to 0. That can't be happening so both are wrong.

Now you have to decide between B and C. The intersection point has Sharon going upwards until she is 20. She started out at 70. The graph has John starting at 70. That's not right.

So we've eliminated A,D and now C.

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2 years ago

What is 14145 divided by 23?

Kobotan [32]

Answer:

615

Step-by-step explanation:

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3 years ago

Read 2 more answers

Find all the roots of the equation x4 - 2x3 + 14x2 - 18x + 45 = 0 given that 1 + 2i is one of its roots.

patriot [66]

Asked and answered elsewhere.
brainly.com/question/10192511

Knowing that 1+2i is a root, you also know that 1-2i is a root, so one quadratic factor is
(x -1)² -(2i)² = x^2 -2x +5

Long division of the given polynomial by this quadratic gives a quotient of
x² +9
which has roots ±3i.

Then all the roots are {-3i, 3i, 1-2i, 1+2i}.

7 0

3 years ago

Three consecutive odd integers have a sum of 27. Find the integers.

jek_recluse [69]

$\sf \bf {\boxed {\mathbb {GIVEN:}}}$

Sum of three consecutive odd integers = $27$

$\sf \bf {\boxed {\mathbb {TO\:FIND:}}}$

The values of the three integers.

$\sf \bf {\boxed {\mathbb {SOLUTION:}}}$

$\sf\purple{The\:three\:consecutive \:odd\:integers\:are\:7,\:9\:and\:11.}$

$\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}$

Let us assume the three consecutive odd integers to be $x$ , $(x+2)$ and $(x+4)$ .

As per the condition, we have

$Sum \: \: of \: \: the \: \: three \: \: consecutive \: \: odd \: \: integers = 27$

$➺ \: x + (x + 2) + (x + 4) = 27$

$➺ \: x + x + 2 + x + 4 = 27$

Now, collect the like terms.

$➺ \: (x + x + x) + (2 + 4) = 27$

$➺ \: 3x + 6 = 27$

$➺ \: 3x = 27 - 6$

$➺ \: 3x = 21$

$➺ \: x = \frac{21}{3} \\$

$➺ \: x = 7$

Therefore, the three consecutive odd integers whose sum is $27$ are $\boxed{ 7 }$ , $\boxed{ 9 }$ and $\boxed{ 11 }$ respectively.