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Sindrei [870]
2 years ago
14

Special Triangle: Solve for x and y.

Mathematics
1 answer:
Lelechka [254]2 years ago
3 0

Answer:

<em><u>x </u></em><em><u>=</u></em><em><u> </u></em><em><u>8</u></em><em><u>.</u></em><em><u>6</u></em><em><u>7</u></em><em><u> </u></em><em><u>and </u></em><em><u>y </u></em><em><u>=</u></em><em><u> </u></em><em><u>1</u></em><em><u>0</u></em>

Step-by-step explanation:

In right angled triangle

cos 60⁰ = 5/y

1/2 = 5/y

y = 10

in right angled triangle,

tan 60⁰ = x/5

√3 = x/5

x = 5√3 = 5 × 1.73 = 8.65

x = 8.67

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Veseljchak [2.6K]

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Btw, the absolute sign is ||, not //.


5 0
3 years ago
What is the most logical first step in solving the equation x2 + 6x +9 = 10?
Shalnov [3]

Answer:

<u>D</u>

Step-by-step explanation:

The logical step is to <u>factorize the left side of the equation</u>, which becomes:

  • (x + 3)² = 10

Then, you can take the square root on both sides.

  • x + 3 = ±√10
  • x = ±√10 - 3

Not asked, but good to understand the procedure regardless.

8 0
2 years ago
In the city there are two options for taxi companies. The Green Company charges $.38 for each 15 of a mile. The Orange Company c
stealth61 [152]
A customer cannot travel orange company if they have $10
4 0
3 years ago
What is 3 divided by 1/6?
Alex777 [14]

Answer:

18

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
How does the speed of a runner vary over the course of a marathon (a distance of 42.195 km)? Consider determining both the time
Tom [10]

Answer:

The observed typical difference value of mode is 100 seconds approximately.

The proportion of runners ran the late distance more quickly than the early distance is approximately 1%

Step-by-step explanation:

Fundamentals

Consider that there are x favorable cases to an event E, out of a total of n cases. Then, the probability of that event is written as:

P(E)=  

Total number of cases /Number of favorable cases =  x/n

A histogram is constructed for continuous data, which is divided into classes called bins. The shape of the distribution can be determined from the histogram.

step 1

The provided histogram indicates time difference on xx -axis and frequency of runners on yy -axis. To determine the typical difference value, identify the peaks of the graph.

The histogram is skewed towards right side. The graph indicates that there are few outliers around 700 seconds. For a typical difference value, the value of mode is considered.

The graph indicates that the value of mode is 100 seconds approximately.

The observed typical difference value of mode is 100 seconds approximately.

Explanation

From the histogram, the typical difference value is obtained on the basis of guessing the value of mode which has been approximated to be around 100 seconds.

Step 2

From the histogram, it can be estimated that there are around 10 runners which has negative difference which means approxi8matley 10 runners ran the late distance more quickly than the early distance,

The approximate sample size can be calculated as:

Sample size=90+190+180+160+120+80+60+40+30+20

Thus, the proportion of runners is obtained as:

\begin{array}{c}\\p = \frac{{\left( \begin{array}{l}\\{\rm{Number of runners who has }}\\\\{\rm{negative time difference}}\\\end{array} \right)}}{{{\rm{Total sample size}}}}\\\\ = \frac{{10}}{{970}}\\\\ = 0.01\\\end{array}  

p=  <u> </u>Number of runners who has

<u>     negative time difference   </u>

      Total sample size

​  

=10/970

=0.001

The proportion of runners ran the late distance more quickly than the early distance is approximately 1%

EXPLANATION

The obtained proportion is 0.01. It indicates that there are approximately 1% of the runners who ran late distance more quickly than the early distance is very few.

​  

​  

3 0
3 years ago
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