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puteri [66]
2 years ago
5

There are three containers filled with different gases as shown.

Mathematics
1 answer:
Natali [406]2 years ago
5 0

\qquad\qquad\huge\underline{{\sf Answer}}

As we know,

\sf \qquad density =  \dfrac{mass}{volume}

So, we can infer that :

\sf \qquad mass= {density} \cdot{volume}

Now, let's calculate the mass of gases in each case :

<h3>Case A : Hydrogen ~</h3>

\qquad \sf  \dashrightarrow \:mass = 0.09 \times (15) {}^{3}

\qquad \sf  \dashrightarrow \:mass = 0.09 \times 3375 {}^{}

\qquad \sf  \dashrightarrow \:mass = 303.75 \:  \: mg {}^{}

or

\qquad \sf  \dashrightarrow \:mass =0. 30375 \:  \: g {}^{}

<h3>Case B : Helium ~ </h3>

\qquad \sf  \dashrightarrow \:mass =0. 175 \:  \cdot  \: (14 \sdot 12 \sdot10)

\qquad \sf  \dashrightarrow \:mass =0. 175 \:  \cdot  \: 1680

\qquad \sf  \dashrightarrow \:mass =0. 175 \:  \cdot  \: 294 \: \:  mg

or

\qquad \sf  \dashrightarrow \:mass = 0.294 \:  \: g

<h3>Case C : Nitrogen ~ </h3>

\qquad \sf  \dashrightarrow \:mass = 1.251\:  \cdot  \: \dfrac{4}{3}  \cdot3.14 \cdot(4) {}^{3}

\qquad \sf  \dashrightarrow \:mass = 0.417\:  \cdot  \: 803.84

\qquad \sf  \dashrightarrow \:mass = 335.201 \:  \: mg

or

\qquad \sf  \dashrightarrow \:mass = 0.335 \:  \: g

So, the arrangement of masses from least to greatest is :

  • (1.) Hydrogen < (2.) Helium < (3.) Nitrogen
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