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puteri [66]
2 years ago
5

There are three containers filled with different gases as shown.

Mathematics
1 answer:
Natali [406]2 years ago
5 0

\qquad\qquad\huge\underline{{\sf Answer}}

As we know,

\sf \qquad density =  \dfrac{mass}{volume}

So, we can infer that :

\sf \qquad mass= {density} \cdot{volume}

Now, let's calculate the mass of gases in each case :

<h3>Case A : Hydrogen ~</h3>

\qquad \sf  \dashrightarrow \:mass = 0.09 \times (15) {}^{3}

\qquad \sf  \dashrightarrow \:mass = 0.09 \times 3375 {}^{}

\qquad \sf  \dashrightarrow \:mass = 303.75 \:  \: mg {}^{}

or

\qquad \sf  \dashrightarrow \:mass =0. 30375 \:  \: g {}^{}

<h3>Case B : Helium ~ </h3>

\qquad \sf  \dashrightarrow \:mass =0. 175 \:  \cdot  \: (14 \sdot 12 \sdot10)

\qquad \sf  \dashrightarrow \:mass =0. 175 \:  \cdot  \: 1680

\qquad \sf  \dashrightarrow \:mass =0. 175 \:  \cdot  \: 294 \: \:  mg

or

\qquad \sf  \dashrightarrow \:mass = 0.294 \:  \: g

<h3>Case C : Nitrogen ~ </h3>

\qquad \sf  \dashrightarrow \:mass = 1.251\:  \cdot  \: \dfrac{4}{3}  \cdot3.14 \cdot(4) {}^{3}

\qquad \sf  \dashrightarrow \:mass = 0.417\:  \cdot  \: 803.84

\qquad \sf  \dashrightarrow \:mass = 335.201 \:  \: mg

or

\qquad \sf  \dashrightarrow \:mass = 0.335 \:  \: g

So, the arrangement of masses from least to greatest is :

  • (1.) Hydrogen < (2.) Helium < (3.) Nitrogen
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which ordered pairs in the form (x, y) are solutions to the equation 3x−4y=21 ? Select each correct answer. (−1, −6) (−3, 3) (11
Valentin [98]

Answer:

see explanation

Step-by-step explanation:

To determine which ordered pairs are solutions to the equation

Substitute the x and y values into the left side of the equation and if equal to the right side then they are a solution.

(- 1, - 6)

3(- 1) - 4(- 6) = - 3 + 24 = 21 = right side ← thus a solution

(- 3, 3)

3(- 3) - 4(3) = - 9 - 12 = - 21 ≠ 21 ← not a solution

(11, 3)

3(11) - 4(3) = 33 - 12 = 21 = right side ← thus a solution

(7, 0)

3(7) - 4(0) = 21 - 0 = 21 = right side ← thus a solution

The ordered pairs (- 1, - 6), (11, 3), (7, 0) are solutions to the equation

3 0
3 years ago
Read 2 more answers
He volume of a rectangular prism is 2,058 cubic cm. The length of the prism is 3 times the width. The height is twice the width.
MrMuchimi

Answer: the height of the prism is 14 cm.

Step-by-step explanation:

The formula for determining the volume of a rectangular prism is expressed as

Volume = length × height × width

Volume = LWH

The length of the prism is 3 times the width. It means that

L = 3W

The height is twice the width. This means that

H = 2W

Therefore,

Volume = 3W × × W × 2W = 6W³

The volume of a rectangular prism is 2,058 cubic cm. This means that

2058 = 6W³

Dividing through by 6, it becomes

343 = W³

W = 7

Therefore, the height of the prism would be

H = 2W = 2 × 7

H = 14 cm

3 0
3 years ago
PLEASE HELP I WILL MARK YOU BRAINLIEST<br><br> FIND THE AREA OF NUMBER 3 AND 4
scoray [572]

Answer:

3. 112.2 yd

4. 30m

Step-by-step explanation:

Number 3:

  1. L × W (length × width) = A
  2. 18.7 × 6 = 112.2 yd

Number 4:

  1. B × H (base × height) = A
  2. 6 × 5 = 30 m

I hope this helps!

8 0
3 years ago
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Solve <br> 1)3x-7=35?<br> 2)22=7-3a<br> 3)-d+7=3<br> 4)2x+23=49<br> 5)-c+2=5
astra-53 [7]
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3)\ -d+7=3\ \ \ \ \ |subtract\ 7\ from\ both\ sides\\\\-d=-4\\\\\boxed{d=4}\\---------------------------\\\\4)\ 2x+23=49\ \ \ \ \ \ |subtract\ 23\ from\ both\ sides\\\\2x=26\ \ \ \ \ \ |divide\ both\ sides\ by\ 2\\\\\boxed{x=13}\\---------------------------\\5)\ -c+2=5\ \ \ \ \ \ |subtract\ 2\ from\ both\ sides\\\\-c=3\\\\\boxed{c=-3}
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3 years ago
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Find an equation of the line. Write the equation using function notation.
Gemiola [76]

The equation of line perpendicular to 4y = x-8 passing through (3,-3) is:

y = -4x+9

Step-by-step explanation:

Given equation of line is:

4y=x-8

We have to convert the given line in slope-intercept form to find the slope of the line

So,

Dividing both sides by 4

\frac{4y}{4} =\frac{x-8}{4}\\y = \frac{1}{4}x-\frac{8}{4}\\y = \frac{1}{4}x-2

Let m1 be the slope of given line

Then

m_1 = \frac{1}{4}\\

Let m2 be the slope of line perpendicular to given line

As we know that produt of slopes of two perpendicular lines is -1

m_1.m_2 = -1\\\frac{1}{4} . m_2 = -1\\m_2 = -1*4\\m_2 = -4

The slope intercept form of line is given by:

y = m_2x+b

Putting the value of slope

y = -4x+b

to find the value of b, putting (3,-3) in equation

-3 = (-4)(3) + b\\-3 = -12 +b\\b = -3+12\\b = 9

Putting the value of b in the equation

y = -4x+9

Hence,

The equation of line perpendicular to 4y = x-8 passing through (3,-3) is:

y = -4x+9

Keywords: Equation of line, slope

Learn more about equation of line at:

  • brainly.com/question/4837736
  • brainly.com/question/4805611

#LearnwithBrainly

4 0
3 years ago
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