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iogann1982 [59]
2 years ago
10

IF YOU CAN ANSWER CORRECTLY I WILL MARK YOU BRAINLIEST

Mathematics
2 answers:
34kurt2 years ago
4 0

Answer:

1,436.75 cubic millimeters

Or

1,436 cubic millimeters

Step-by-step explanation:

bogdanovich [222]2 years ago
3 0
Hi, the answer is 1436.76

Hope I’ve helped!
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HELP me please look at the picture
Effectus [21]
The answer is 17 you are correct
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What is (w-4/9) (-2/3) =-4/9
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W=10/9 is the answer
8 0
3 years ago
Please answer this question
Alina [70]

Answer:

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12 x 4 x 7 + 1

__

Step-by-step explanation:

The biggest number can be made by multiplying all the numbers. However, since one of these numbers is 1, multiplying 1 by all those others won’t do anything. So to get the biggest number you would multiply 12 by 4 by 7 and add 1.

3 0
3 years ago
A triangle is 3 units wide and 5 units high.
Oksana_A [137]

Answer:

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Step-by-step explanation:

i thnk u can figure this out

8 0
3 years ago
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Memory module consists of 9 chips. The device is designed with redundancy so that it works even if one of its chips is defective
soldier1979 [14.2K]

Answer:

a) P[C]=p^n

b) P[M]=p^{8n}(9-8p^n)

c) n=62

d) n=138

Step-by-step explanation:

Note: "Each chip contains n transistors"

a) A chip needs all n transistor working to function correctly. If p is the probability that a transistor is working ok, then:

P[C]=p^n

b) The memory module works with when even one of the chips is defective. It means it works either if 8 chips or 9 chips are ok. The probability of the chips failing is independent of each other.

We can calculate this as a binomial distribution problem, with n=9 and k≥8:

P[M]=P[C_9]+P[C_8]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)\\\\P[M]=p^{8n}(p^{n}+9(1-p^n))\\\\P[M]=p^{8n}(9-8p^n)

c)

P[M]=(0.999)^{8n}(9-8(0.999)^n)=0.9

This equation was solved graphically and the result is that the maximum number of chips to have a reliability of the memory module equal or bigger than 0.9 is 62 transistors per chip. See picture attached.

d) If the memoty module tolerates 2 defective chips:

P[M]=P[C_9]+P[C_8]+P[C_7]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1+\binom{9}{7}P[C]^7(1-P[C])^2\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])+36P[C]^7(1-P[C])^2\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)+36p^{7n}(1-p^n)^2

We again calculate numerically and graphically and determine that the maximum number of transistor per chip in this conditions is n=138. See graph attached.

6 0
4 years ago
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