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damaskus [11]
2 years ago
13

Jessie and Jaime complete a 5.0 km race. Each has a mass of 68 kg. Jessie runs the race at 15 km/h; Jaime walks it at 5 km/h. Ho

w much metabolic energy does each use to complete the course
Physics
1 answer:
Leto [7]2 years ago
5 0

The total metabolic energy used by each to complete the course is determined as 656.91 J.

<h3>Kinetic energy of Jessie and Jaime</h3>

The kinetic energy of Jessie and Jaime is calculated as follows;

K.E = ¹/₂mv²

where;

  • m is mass of Jaime
  • v is speed

15 km/h = 4.17 m/s

5 km/h = 1.39 m/s

K.E = ¹/₂(68)(4.17)² + ¹/₂(68)(1.39)²

K.E = 656.91 J

Thus, the total metabolic energy used by each to complete the course is determined as 656.91 J.

Learn more about kinetic energy here: brainly.com/question/25959744

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Almonds cost $3.49 per pound. A bag of almonds costs $6.95. to the nearest whole pound, about how many pounds of almonds are in
abruzzese [7]

The hint in this problem is in the word "about" or approximately how many pounds.

So we could find the solution by estimation through rounding off.

 

We know that almonds cost about 3.50 per pound and a bag costs about $7.00.

Dividing 7 by 3.50 per pound, will give us $7 ÷ $3.50 = 2 pounds.

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3 0
3 years ago
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Consider a air-filled parallel-plate capacitor with plates of length 8 cm, width 5.52 cm, spaced a distance 1.99 cm apart. Now i
prohojiy [21]

Answer:

The ratio of the new potential energy to the potential energy before the insertion of the dielectric is 0.58

Explanation:

Given that,

Length of plates = 8 cm

Width = 5.52 cm

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Length = 4.4 cm

Potential = 0.8 V

We need to calculate the initial capacitance

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C=\dfrac{\epsilon_{0}A}{d}

Put the value into the formula

C=\dfrac{8.85\times10^{-12}\times8\times5.52\times10^{-4}}{1.99\times10^{-2}}

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We need to calculate the final capacitance

Using formula of capacitance

C'=\dfrac{\epsilon_{0}A_{1}}{d}+\dfrac{k\epsilon_{0}A_{2}}{d}

Put the value into the formula

C'=(\dfrac{8.85\times10^{-12}}{1.99\times10^{-2}})((4.4\times5.52)+(3.6\times5.52)2.6)\times10^{-4}

C'=3.37\times10^{-12}

We need to calculate the  ratio of the new potential energy to the potential energy before the insertion of the dielectric

Using formula of energy

\dfrac{E}{E'}=\dfrac{\dfrac{1}{2}CV^2}{\dfrac{1}{2}C'V^2}

Put the value into the formula

\dfrac{E}{E'}=\dfrac{1.96\times10^{-12}}{3.37\times10^{-12}}

\dfrac{E}{E'}=0.58

Hence, The ratio of the new potential energy to the potential energy before the insertion of the dielectric is 0.58

4 0
3 years ago
1. Which segment on this position vs time graph represents the object returning back to the origin?
Monica [59]

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Answer:

  D. Segment D

Explanation:

The origin is represented on the graph by the position (y-value) being 0. The portion of the graph that shows position being non-zero and ending at 0 is the portion marked <em>segment D</em>.

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Which circuit would have the most electrical power? O A. 1 = 3.2 A V = 0.12 V OB. 1 = 2.5 A V = 0.22 OC 1=3.3 A V=0.09 V OD 1 =
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Answer:

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Explanation:

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