D. It happens all the time
The relevant formula we can use in this case would be:
h = v0 t + 0.5 g t^2
where,
h = height or distance travelled
v0 = initial velocity = 0 since it was dropped
t = time = 1 seconds
g = 9.8 m/s^2
So calculating for height h:
h = 0 + 0.5 * 9.8 m/s^2 * (1 s)^2
<span>h = 4.9 meters</span>
Answer:
3.7kg
Explanation:
The following data were obtained from the question:
Volume = 3.7L
Mass =?
Next, we shall convert 3.7L to m³.
This is illustrated below:
1000L = 1m³
Therefore, 3.7L = 3.7/1000 = 0.0037m³
Now, we can obtain the mass of the water as shown below:
Density of water = 1000kg/m³
Volume of water = 0.0037m³
Mass of water =..?
Density = Mass /volume
1000kg/m³ = Mass /0.0037m³
Cross multiply
Mass = 1000Kg/m³ × 0.0037m³
Mass = 3.7Kg
Therefore, the mass of the water is 3.7Kg.
