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qwelly [4]
3 years ago
14

What is the sum of m and 8

Mathematics
1 answer:
TEA [102]3 years ago
7 0

Answer:

m+8

Step-by-step explanation:

Since m is an unknown variable, the only thing we can say is that the sum of m and 8 is m+8

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Suppose the following number of defects has been found in successive samples of size 100: 6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6
Brut [27]

Answer:

Given the data in the question;

Samples of size 100: 6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6, 10, 9, 2, 8, 4, 8, 10, 10, 8, 7, 7, 7, 6, 14, 18, 13, 6.

a)

For a p chart ( control chart for fraction nonconforming), the center line and upper and lower control limits are;

UCL = p" + 3√[ (p"(1-P")) / n ]

CL = p"

LCL = p" - 3√[ (p"(1-P")) / n ]

here, p" is the average fraction defective

Now, with the 30 samples of size 100

p" =  [∑(6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6, 10, 9, 2, 8, 4, 8, 10, 10, 8, 7, 7, 7, 6, 14, 18, 13, 6.)] / [ 30 × 100 ]

p" = 234 / 3000

p" = 0.078

so the trial control limits for the fraction-defective control chart are;

UCL = p" + 3√[ (p"(1-P")) / n ]

UCL = 0.078 + 3√[ (0.078(1-0.078)) / 100 ]

UCL = 0.078 + ( 3 × 0.026817 )

UCL = 0.078 + 0.080451

UCL = 0.1585

LCL = p" - 3√[ (p"(1-P")) / n ]

LCL = 0.078 - 3√[ (0.078(1-0.078)) / 100 ]

LCL = 0.078 - ( 3 × 0.026817 )

LCL = 0.078 - 0.080451

LCL =  0 ( SET TO ZERO )

Diagram of the Chart uploaded below

b)

from the p chart for a) below, sample 28 violated the first western electric rule,

summary report from Minitab;

TEST 1. One point more than 3.00 standard deviations from the center line.

Test failed at points: 28

Hence, we conclude that the process is out of statistical control

Lets Assume that assignable causes can be found to eliminate out of control points.

Since 28 is out of control, we should eliminate this sample and recalculate the trial control limits for the P chart.

so

p" = 0.0745

UCL = p" + 3√[ (p"(1-P")) / n ]

UCL = 0.0745 + 3√[ (0.0745(1-0.0745)) / 100 ]

UCL = 0.0745 + ( 3 × 0.026258 )

UCL = 0.0745 + 0.078774

UCL = 0.1532

LCL  = p" - 3√[ (p"(1-P")) / n ]

LCL = 0.0745 - 3√[ (0.0745(1-0.0745)) / 100 ]

LCL = 0.0745 - ( 3 × 0.026258 )

LCL = 0.0745 - 0.078774

UCL = 0  ( SET TO ZERO )

The second p chart diagram is upload below;

NOTE; the red circle symbol on 28 denotes that the point is not used in computing the control limits

7 0
2 years ago
The area of a triangular block is 16 squre inches. If the base of the triangle is twice the height, how long are the base and th
klemol [59]
The area of a triangle can be calculated using the formula 

1/2 (base) (height)

Let's substitute our known values, letting x represent the value of the height of the triangle.

16  = 1/2* x* 2x

Let's Simplify!

16 = x^2

Finally, lets take the square root of both sides, to get rid of the exponent on the right side of the equation.

x= positive OR negative 4.

However, because x is equal to the height, we know that it can't be negative, so we know that it is positive 4.

The height of the triangle = 4 inches
The base of the triangle = 2h = 8 inches

6 0
3 years ago
Can someone help me :(
White raven [17]

Answer:

19 ft.

Step-by-step explanation:

Pytahgorean theorm. A^2 + B ^2 = C^2

49 + 100 = 149

Square root the 149, which is ~12

That means the hypotenuse is twelve feet, and with the base of the pole being seven, the pole was originally 19 feet tall.

4 0
3 years ago
Read 2 more answers
For which positive integer values of $k$ does $kx^2+20x+k=0$ have rational solutions? Express your answers separated by commas a
Musya8 [376]

Answer:

-10,10

Step-by-step explanation:

The given quadratic equation is

k {x}^{2}  + 20x + k = 0

The discriminant of this equation is given by;

D =  {b}^{2}  - 4ac

where a=k, b=20, c=k

For rational solutions, the discriminant must be zero.

{20}^{2}  - 4 \times k \times k = 0

Simplify to get:

400 - 4  {k}^{2}  = 0

This implies that:

400  = 4  {k}^{2}

100 =  {k}^{2}

Take square root to get:

k =   \pm\sqrt{100}

k =  \pm10

k =  - 10 \: or \: k = 10

3 0
3 years ago
|j|=|2j+3| please help me
Softa [21]
Simplifying
j = (2j + 3)

Reorder the terms:
j = (3 + 2j)

Remove parenthesis around (3 + 2j)
j = 3 + 2j

Solving
j = 3 + 2j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-2j' to each side of the equation.
j + -2j = 3 + 2j + -2j

Combine like terms: j + -2j = -1j
-1j = 3 + 2j + -2j

Combine like terms: 2j + -2j = 0
-1j = 3 + 0
-1j = 3

Divide each side by '-1'.
j = -3

Simplifying
j = -3
8 0
3 years ago
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