The first derivative of the function f(x) = x² - 5 is equal to f'(x) = 2 · x.
<h3>How to find the derivative of a quadratic equation by definition of derivative</h3>
In this question we have a quadratic function, in which we must make use of the definition of derivative to find the expression of its first derivative. Then, the procedure is shown below:
f(x) = x² - 5 Given
f' = [(x + h)² - 5 - x² + 5] / h Definition of derivative
(x² + 2 · x · h + h² - 5 - x² + 5) / h Perfect square trinomial
(2 · x · h + h²) / h Associative, commutative and modulative properties / Existence of additive inverse
2 · x + h Distributive, commutative and associative properties / Definition of division / Existence of multiplicative inverse
2 · x h = 0 / Result
The first derivative of the function f(x) = x² - 5 is equal to f'(x) = 2 · x.
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Answer:
5, assuming you get the worst possible slips off: 0,1,2,3,4
Step-by-step explanation:
Answer:
B) 10g
Step-by-step explanation:
Collect like terms
8g + 4g - 2g = 10g
2 - 2 = 0
10g + 0= 0
If there are 400 silver dollars in all, and there are 275 in one bag, to find the amount in the other bag, just subtract:
400-275=125
There are 125 in the other bag.
Answer:
Step-by-step explanation:
The polynomial is simplified by combining like terms. Like terms are identified more easily if the variables in each term are written in the same order. We usually like to use alphabetical order. Two of the like terms have opposite coefficients, so they cancel. The result is ...
(3 1/2 -2 1/2)xy² +(-2 4/5 +2 4/5)x²y
= xy² . . . . simplified expression
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For x = 1, y = -2, the value of the expression is ...
(1)(-2)² = 4
