Answer & Explanation:
(a)

reducing agent = Fe²⁺
Oxidizing agent = NO₃⁻
oxidation
Fe²⁺ ⇒ Fe(OH)₃
reduction
NO₃⁻ ⇒ N₂
Oxidation Half Reaction
(<em>redox reactions are balanced by adding appropriate H⁺ and H₂O atoms)</em>
Fe²⁺ ⇒ Fe(OH)₃
Balance O atoms
Fe²⁺ + 3H₂O ⇒ Fe(OH)₃
Balance H atoms
Fe² + 3H₂0 ⇒ Fe(OH)₃ + 3H⁺
balance Charge
Fe² + 3H₂0 ⇒ Fe(OH)₃ + 3H⁺ + e⁻..............(1)
reduction Half Reaction
NO₃⁻ ⇒ N₂
Balance N atoms
2NO₃⁻ ⇒N₂
Balance O atoms by adding appropriate H₂O
2NO₃⁻ ⇒ N₂ + 6H₂O
Balance H atoms
2NO₃⁻ + 12H⁺ ⇒ N₂ + 6H₂O
Balance Charge
2NO₃⁻ + 12H⁺ + 10e⁻⇒ N₂ + 6H₂O.................(2)
Combine Equation (1) and (2)
(1) × 10: 10Fe² + 30H₂0 ⇒ 10Fe(OH)₃ + 30H⁺ + 10e⁻
(2) × 1: 2NO₃⁻ + 12H⁺ + 10e⁻⇒ N₂ + 6H₂O
(1) + (2): 10Fe² + <u><em>30H₂0</em></u> + 2NO₃⁻ + <u><em>12H⁺</em></u> + <u><em>10e⁻</em></u> ⇒10Fe(OH)₃ + <u><em>30H⁺</em></u><u><em> </em></u>+ <em><u>10e⁻</u></em> +
N₂ + <u><em>6H₂O</em></u>
10Fe² + 24H₂0 + 2NO₃⁻ ⇒ 10Fe(OH)₃ + 18H⁺ + N₂
this is the balanced reaction
REDUCTION POTENTIAL
10Fe²⁺(aq) + 10e⁻ ⇒ 10Fe(OH)₃(aq) E°ox = 10(-0.44) = -4.4V
2NO₃⁻(aq) - 2e⁻ ⇌ N₂(g) + 18H⁺ E°red = 2(+0.80) = +1.6
10Fe² + 24H₂0 + 2NO₃⁻ ⇒ 10Fe(OH)₃ + 18H⁺ + N₂ E°cell = -2.8V
E°cell = E°red + E°ox
Answer: The atomic weight of the metal would be 85.47.
Explanation:
Mass of isotope 1 of metal = 84.9118
% abundance of isotope 1 of metal = 72.15% =
Mass of isotope 2 of metal= 86.9092
% abundance of isotope 2 of metal = 27.85% =
Formula used for average atomic mass of an element :

Therefore, the atomic weight of the metal would be 85.47.
Answer: The partial pressure of the Kr is 320 mm Hg.
Explanation:
According to Raoult's Law , the partial pressure of each component in the solution is equal to the total pressure multiplied by its mole fraction. It is mathematically expressed as

where,
= partial pressure of component A
= mole fraction of A
= total pressure
mole fraction of Krypton = 

Thus partial pressure of the Kr is 320 mm Hg
Answer:
850 Calories.
Explanation:
The following data were obtained from the question:
Mass (M) = 50 g
Initial temperature (T1) = 20 °C
Final temperature (T2) = 37 °C
Specific heat capacity (C) of water = 1 cal/g°C
Heat absorbed (Q) =..?
Next, we shall determine the change in temperature of water.
This can be obtained as follow:
Initial temperature (T1) = 20 °C
Final temperature (T2) = 37 °C
Change in temperature (ΔT) =..?
Change in temperature (ΔT) = T2 – T1
Change in temperature (ΔT) = 37 – 20
Change in temperature (ΔT) = 17 °C
Finally, we shall determine the heat absorbed. This can be obtained as follow:
Mass (M) = 50 g
Specific heat capacity (C) of water = 1 cal/g°C.
Change in temperature (ΔT) = 17 °C
Heat absorbed (Q) =..?
Q = MCΔT
Q = 50 x 1 x 17
Q = 850 Calories
Therefore, the heat absorbed is 850 Calories.
<span>quartz (SiO2) is a compound. A compud is the combination of two or more elements. It is a compound because three elements are formed, the silicon and the two atoms of oxygen.</span>