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77julia77 [94]
3 years ago
6

I made a cup of coffee on the stove and when I went to check on it four hours later, there was no more water in the kettle.

Chemistry
2 answers:
777dan777 [17]3 years ago
8 0
I believe so; you might want to take cover. It's dangerous out there. 
11Alexandr11 [23.1K]3 years ago
3 0
No the water evaporated 
i think :) :) 

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Vanillin (used to flavour vanilla ice cream and other foods) is the substance whose aroma the human nose detects in the smallest
Rudiy27

Answer:

The cost is $0.063.

Explanation:

First, we need to express the volume of the hangar in liters. We know that 1 ft³ = 28.31 L, so using proportions:

5.0 \times 10^{7} ft^{3} .\frac{28.31L}{1ft^{3} } =1.4 \times 10^{9} L

The amount of vanillin required would be:

1.4 \times 10^{9} L.\frac{2.0\times 10^{-11}g }{1L} =0.028g

Finally, the price for such amount of vanillin is:

0.028g.\frac{ \textdollar 112}{50g}=  \textdollar 0.063

6 0
3 years ago
Calculate the number of moles in the 2.1-L volume of air in the lungs of the average person. Note that the air is at 37.0ºC (bod
adelina 88 [10]
Answer: 0.0826mol

PV=nRT
n=PV/RT
n=(1atm)(2.1L)/(310K)(0.082057L*atm/mol*K)=0.0826mol
7 0
3 years ago
What is the mass of 0.714 moles of Mercury (I) Chloride (Hg2Cl2)?
ArbitrLikvidat [17]
Data:

m (<span>Sample Mass) = ? 
n (</span><span>Number of moles) = 0.714 mol
MM (Molar Mass) of </span>Mercury (I) Chloride (Hg_{2}  Cl_{2})
Hg = 2*200.59 = 401.18 amu
Cl = 2*35.453 = 70.906 amu
----------------------------------------
Molar Mass Hg_{2} Cl_{2} = 401.18 + 70.906 = 472.086 ≈ 472.09<span> amu or 472.09 g/mol
</span>
Formula:

n =  \frac{m}{MM}

Solving:


n = \frac{m}{MM}
0.714 =  \frac{m}{472.09}
m = 337.07226\:\to\:\boxed{\boxed{m\approx 337 g}} \end{array}}\qquad\quad\checkmark

Answer:
By approximation would be letter D) <span>337.2 g</span>


8 0
3 years ago
A gas sample is found to contain 39.10% carbon, 7.67% hydrogen, 26.11% oxygen, 16.82% phosphorus, and 10.30% fluorine. If the mo
Doss [256]

Answer:

C6H14O3F

Explanation:

The first step is to divide each compound by its molecular weight

Carbon

= 39.10/12

= 3.258

Hydrogen

= 7.67/1

= 7.67

Oxygen

= 26.11/16

= 1.63

Phosphorous

= 16.82/31

= 0.542

Flourine

= 10.30/19

= 0.542

The next step is to divide by the lowes value

3.258/0.542

= 6 mol of C

7.67/0.542

= 14 mol of H

1.63/0.542

= 3 mol of O

0.542/0.542

= 1 mol of P

0.542/0.542

= 1 mol of F

Hence the molecular formula is C6H14O3F

5 0
2 years ago
What is the mass of 5 mole of ammonia . Calculate the number of NH₃ molecules, nitrogen atom and hydrogen atoms in it..
Aloiza [94]

Molar mass of NH_3

\\ \sf\longmapsto 14u+3(1u)

\\ \sf\longmapsto 14u+3u

\\ \sf\longmapsto 17g/mol

We know.

No of moles=Given mass/Molar mass

\\ \sf\longmapsto Given\;Mass=17(5)

\\ \sf\longmapsto Given \:Mass\:of\:NH_3=85g

Now

Lets write the balanced equation

\\ \sf\longmapsto N_2+3H_2=2NH_3

  • There is 2moles of Ammonia
  • 3moles of H_2
  • 1mole of N_2

Now

\boxed{\sf No\:of\:Molecules =No\:of\;moles\times Avagadro\:no}

For Hydrogen

\\ \sf\longmapsto 3\times 6.023\times 10^{23}

\\ \sf\longmapsto 18.069\times 10^{23}

\\ \sf\longmapsto 1.8\times 10^{22}molecules

For Ammonia

\\ \sf\longmapsto 2\times 6.023\times 10^{23}

\\ \sf\longmapsto 12.046\times 10^{23}

\\ \sf\longmapsto 1.2\times 10^{22}molecules

For Nitrogen

\\ \sf\longmapsto 1\times 6.023\times 10^{23}

\\ \sf\longmapsto 6.023\times 10^{23}molecules

3 0
2 years ago
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