All categories

4 years ago

When iron (II) hydroxide is mixed with phosphoric acid, iron (II) phosphate precipitate results.

Chemistry

1 answer:

Triss [41]4 years ago

3 0

Answer:

a. Fe(OH)2

b. H3PO4

c. 0.01185 moles

Explanation:

The balanced equation of the question will be:

3 Fe(OH)2 + 2 H3PO4 → Fe3(PO4)2 + 6 H2O

a. what is the limiting reactant?

A limiting reactant is a reactant that will be used up in the reaction. We can find it by calculating the stoichiometric ratio. The reactant with the lowest ratio, which will be depleted first, is the limiting reactant. The reaction will stop if any reactant depleted, so the limiting reactant will be the one that determines how many products made. If you add more of a limiting reactant, the reaction will continue.

The molecular mass of Fe(OH)2 is 90g/mol while the molecular mass of H3PO4 is 98 g/mol. The number of each reactant in moles will be

Fe(OH)2 = 3.20g/ (90g/mol) =0.03555 mol

H3PO4 = 2.50g/ (98g/mol) = 0.02551 mol

The actual ratio of Fe(OH)2 : H3PO4 will be:

0.03555 mol/ 0.02551 mol= 1.393 mol/ 1 mol

The stoichiometric coefficient of Fe(OH)2 is 3 while H3PO4 is 2. Mean you need 3 moles Fe(OH)2 of to for the reaction every 2 moles of H3PO4.

The stoichiometric ratio will be: 3 mol/ 2 mol= 1.5 mol/ 1 mol

Since the actual ratio (1.393) is lower than the stoichiometric ratio(1.5) that means we have less Fe(OH)2 than H3PO4, thus the limiting reactant is the Fe(OH)2.

b. What is the reactant in excess?

The excess reactant is the reactant that will have to remain after the reaction stop. It's the opposite of the limiting reactant. Since we still have remains, adding excess reactant won't continue the reaction.

We already know that Fe(OH)2 is the limiting reactant, then H3PO4 will be the excess reactant. The number of reactant remaining will be:0.02551 mol -0.03555 mol/ (1.5 mol -1 mol)=0.00181 mol

c. What is the theoretical yield

Theoretical yield is the predicted amount of product made if the reaction happens with a 100% yield. To find the yield, we need to know how much reactant used and then multiply it with the stoichiometric coefficient of the product. If Fe(OH)2 the limiting reactant then it means all 0.03555 mol of it will be used. The amount of iron (iii) phosphate made will be:

0.03555 mol * 1/3= 0.01185 moles

You might be interested in

How to economically produce fine greens

nika2105 [10]

Answer:

A transition to renewable energy and to replace fossil fuels would take care of economically producing fine greens. Also, a transition to energy conservation and efficient energy use would help in this process.

Have a great day!

5 0

3 years ago

What’s the answers to these?

nata0808 [166]

Answer:

0bervation

Explanation:

cause it is

5 0

4 years ago

Which is a characteristic of a strong base

Lubov Fominskaja [6]

Answer:

Explanation:

The strong bases have following properties:

1. In solution, strong bases ionize fully.

2. On dissolving the strong bases in water they produce all hydroxide ion which they have.

3. For strong bases the value of equilibrium constant (Kb ) is large.

4. In general the strong base ionizes completely means concentration of ions are greater means conductivity also greater.

5. For strong bases the value of equilibrium constant (Kb) is large, thus the value of dG0 is very large negative number.

6 0

3 years ago

When Z-4,5-dimethyloct-4-ene is treated with hydrogen chloride, HCl, the result is:________.

Vika [28.1K]

Answer:

The correct option is c

Explanation:

The chemical equation for the reaction of Z-4,5-dimethyloct-4-ene and HCl is shown on the first uploaded image

Now looking at the product we see that there are two who has four different groups attached to them this carbon are known as chiral carbons hence the product formed is a pair of diastereomers

6 0

4 years ago

Hno3, a strong acid, is added to shift the ag2co3 equilibrium (equation 7.6) to the right. explain why the shift occurs.

Deffense [45]

Answer 1) When a strong acid like $HNO_{3}$ reacts with $Ag_{2} CO_{3}$ usually the equilibrium shifts to the right because

As per the Le chatelier's principle "if in any reaction, a dynamic equilibrium is disturbed by changing the any of the conditions, the position of equilibrium moves to counteract the change." So, in the given reaction when $HNO_{3}$ reacts with $Ag_{2} CO_{3}$ it generates carbon dioxide and water as a by product, if we are adding $HNO_{3}$ it will remove some of the $CO_{3}$ molecule from the reaction mixture, which then tends to shift the equilibrium towards right.

Answer 2) The same would be observed in this case, if we replace $HNO_{3}$ with HCl it will shift the equilibrium to the right as their will be generation of AgCl as the precipitate.

As per the definition of Le Chatelier's principle if we add reactants in the reaction the equilibrium will tend to move towards right, also if we replace the products or remove it then too it will shift the equilibrium towards right. So, in this reaction you are removing $Ag^{+}$ and $Cl^{-}$ ions from the solution.

7 0

3 years ago