Try moving the magnet in the different ways described in the table below,. Record your observations in the second column of the
1 answer:
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Answer:
S = 122.5m
Explanation:
Given the following data;
Acceleration due to gravity = 9.8m/s²
Time, t = 5 seconds
Since it's a free fall, initial velocity, u = 0
To find the displacement, we would use the second equation of motion given by the formula;
Where;
- S represents the displacement or height measured in meters.
- u represents the initial velocity measured in meters per seconds.
- t represents the time measured in seconds.
- a represents acceleration measured in meters per seconds square.
Substituting into the equation, we have;
S = 122.5m.
Answer:
The magnitude of actual velocity is <u>496.67 mph</u> and its direction is <u>51.54° with the x axis in the third quadrant</u>.
Explanation:
Given:
Speed of jumbo jet in southwesterly direction = 550 mph
Velocity of jet stream from west to east direction
First let us draw a vectorial representation of the above velocity vectors.
Consider the south direction as negative y axis and west direction as negative x axis.
From the diagram,
The velocity of the jet can be represented as:
Similarly, the velocity of the stream is,
Now, the vector sum of the above two vectors gives the actual velocity of the aircraft. So, the resultant velocity is given as:
Now, magnitude is given as the square root of sum of the squares of the 'i' and 'j' components. So,
As the horizontal and vertical components of actual velocity negative, the resultant vector makes an angle with the x axis in the third quadrant.
The direction is given as:
Therefore, the magnitude of actual velocity is 496.67 mph and its direction is 51.54° with the x axis in the third quadrant.
Explanation:
It is given that,
Magnitude of charge,
It moves in northeast direction with a speed of 5 m/s, 25 degrees East of a magnetic field.
Magnetic field,
Velocity,
We need to find the magnitude of force on the charge. Magnetic force is given by :
<em>Since</em>,
So, the force acting on the charge is and is moving in positive z axis. Hence, this is the required solution.