Answer: The block of 0.4 Kg travel the same distance that the block of
0.2 Kg
Explanation: Considering the second newton law, we have the following
F= m*a
F= P*sin (θ) where θ is the angle for the incline
so mg sin (θ)= m*a
a=g sin(θ)
both block have the same acceleration in the inclined plane so travel the same distance independent of its mass.
Answer:
Explanation:
20.1 + 2.00100 +48.28 + 0.015 = 70.396 ≈ 70.4
3 s.f. 6 s.f. 4 s.f. 3 s.f 3 s.f
Answer:
F = 35651 [N]
Explanation:
To solve this problem we must use Newton's second law, which tells us that the sum of forces is equal to the product of mass by acceleration.
But first, we must use the following equation of kinematics to find acceleration.
where:
Vf = final velocity = 185 [m/s]
Vi = initial velocity = 0 (the cannon ball is at rest in the first moment)
a = acceleration [m/s²]
x = distance = 3.6 [m]
Now replacing these values into the equation:
(185)² = 0² + (2*a*3.6)
34225 = 7.2*a
a = 34225/7.2
a = 4753.5 [m/s²]
Now using Newton's second law we have:
F = m*a
where:
F = force [N]
m = mass = 7.5 [kg]
F = 7.5*4753.5
F = 35651 [N]
You have said that 15cm³ of gold weighs 2.8N. So I may infer that each cm³
of gold weighs about 0.19N. When I compare that figure with the 0.13N per cm³
of mercury, it becomes immediately apparent that the gold is more dense than
mercury. Therefore, the sample of gold, no matter what its size or weight, will
displace its total volume of mercury, and will go on to sink entirely beneath the
waves in the mercury.