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klemol [59]
3 years ago
15

A 3-kg chunk of putty moving at 2 m/s collides with and sticks to a 5-kg bowling ball initially at rest. The bowling ball and pu

tty then move with a momentum of
Physics
1 answer:
Oduvanchick [21]3 years ago
4 0

Answer:

It's Momentum becomes 4

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Three cars (car F, car G, and car H) are moving with the same velocity when the driver suddenly slams on the brakes, locking the
nika2105 [10]

Answer:

a) Option D

b) Option A

Explanation:

a) Option D

Because a massive car will have more inertia which will make the car move faster but a massive car simultaneously will have more friction thereby restricting its movement in the forward direction. Hence, all the three cars will move equal distance.

b) Option A, Car F

Being most massive car, the frictional force required to stop the car will be highest.  

4 0
3 years ago
How is carbonic acid responsible for the formation of some caves? ASAP PLEASE!!!!
butalik [34]
It desolves calcium carbonate causing plates to bend and faults to occur. Faults and plates moving cases the formation of caves.

-Hopes this helps :)
4 0
3 years ago
Use the drop-down menus to identify the parts of the
DochEvi [55]

Answer:

Label A: Battery, Label B: Light or Bulb, Label C: Switch

Explanation:

I got it right.

5 0
3 years ago
If he leaves the ramp with a speed of 31.0 m/s and has a speed of 29.5 m/s at the top of his trajectory, determine his maximum h
raketka [301]

Answer:

The maximum height reached is 4.63 m.

Explanation:

Given:

Initial speed of the man (u) = 31.0 m/s

Speed at the top of trajectory (u_x) = 29.5 m/s

Acceleration due to gravity (g) = 9.8 m/s²

When the man reaches the top of the trajectory, the vertical component of velocity becomes zero and hence only horizontal component of velocity acts on him.

Also, since there is no net force acting in the horizontal direction, the acceleration is zero in the horizontal direction from Newton's second law. Thus, the horizontal component of velocity always remains the same.

So, speed at the top of trajectory is nothing but the horizontal component of initial velocity.

Now, initial velocity can be rewritten in terms of its components as:

u^2=u_x^2+u_y^2

Where, u_x\ and\ u_y are the initial horizontal and vertical velocities of the man.

Now, plug in the given values and simplify. This gives,

(31.0)^2=(29.5)^2+u_y^2\\\\961=870.25+u_y^2\\\\u_y^2=961-870.25\\\\u_y^2=90.75\ m^2/s^2--------1

Now, we know that, for a projectile motion, the maximum height is given as:

H=\frac{u_y^2}{2g}

Plug in the value from equation (1) and 9.8 for 'g' to solve for 'H'. This gives,

H=\frac{90.75}{2\times 9.8}\\\\H=4.63\ m

Therefore, the maximum height reached is 4.63 m.

3 0
3 years ago
What happens to the wavelength of a wave if you increase the frequency?
dezoksy [38]

The product of (wavelength) times (frequency) is always the same number ...
the speed of the wave in whatever material it's traveling through.  So if the
frequency is increased, then the wavelength must <em><u>de</u></em>crease by the same
factor, in order to keep the product the same.


4 0
3 years ago
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