Answer:
Explanation:
Let the specific heat of material be s
heat lost by material = m₁ s (T 1 - T ) , (T 1 - T ) is fall in temp , m₁ is mass of material
= .45 x s x (91 - 31.4 )
= 26.82 s
Heat gained by water
= m₂ cw (T2 - T )
1.3 x 4186 x ( 31.4 - 23 )
heat lost = heat gained
m₂ cw (T2 - T ) = m₁ s (T 1 - T )
1.3 x 4186 x ( 31.4 - 23 ) = .45 x s x (91 - 31.4 )
45711.12 = 26.82 s
s = 1704.36
Answer:
Following are the solution to the given points:
Explanation:
For point a:
Find the schematic of the empty body and in attachment. Upon on ball during the pitch only two forces act:
The strength of the pitcher F is applied that operates horizontally. Its gravity force acting on an object is termed weight, which value is where m denotes mass, and g the acceleration of gravity.
For point b:

First, they must find that ball's acceleration. You can use the SUVAT equation to achieve that
where

Solving for a,

Calculating the mass:

Calculating the force:

For point c:
0.195 times the pitcher's weight

Solving for W:

Now the force of Part B could be defined as the fraction of the mass of the pitcher:

They send out waves differently and cannot be heard easily
(18 gallon/tank) x (23 mile/gallon) = <em>414 mile/tank</em>
Answer:
m = 0.255kg
Explanation:
from the formular of a mass - spring system
T = 2π√m/k
making m as the subject of formular
m = T² k/4π²
T =5.91s
k = 0.288 N/m
m = 10.059/39.489
m = 0.255kg