Answer: Option D. 1,778
Solution:
Standard brick:
Width: w=3.625 in
Height: h=2.25 in
Length: l=7.625 in
Volumen of one standard brick: v
v=w*h*l
v=(3.625 in)*(2.25 in)*(7.625 in)
v=62.19140625 in^3
Pallet of bricks:
Side: s=4 feet
s=(4 feet)*(12 in / 1 feet)→s=48 in
Volume of a pallet of bricks: V=s^3
V=(48 in)^3
V=110,592 in^3
Number of bricks could be in a pallet: n
n=V/v
n=(110,592 in^3) / (62.19140625 in^3)
n=1,778.252119
n=1,778
It is D because all the numbers range from 12 to 23, with no number being extremely low or high compared this range.
Start with the equation,
V = 2s^3
Now substitute s with 3.5 units and evaluate the expression.
V = 2 * (3.5 units)^3
V = 2 * 42.875 units^3
V = 85.75 units^3
Answer: The volume is 85.75 cubic units
Answer:
I thought if you try to do an exponent on a zero, then the answer would always be undefined...
Step-by-step explanation:
Answer:
4/x^7
Step-by-step explanation:
4x^-7 = 4* x^-7 = 4* 1/x^7 = 4/x^7