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3 years ago

14

The standard normal distribution has a mean of and a standard deviation of

1 answer:

Anna007 [38]3 years ago

3 0

The standard normal distribution has a mean of 0 and a standard deviation of 1

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Find the area of a triangle with a =33, b =51, and c =42.

PolarNik [594]

Answer:

d. 690.1 units²

Step-by-step explanation:

1. You can use the Heron's formula to calculate the area of the triangle, which is:

$K=\sqrt{s(s-a)(s-b)(s-c)}$

Where:

$s=\frac{a+b+c}{2}$

2. Calculate $s$ :

$s=\frac{33+51+42}{2}\\s=63$

3. Substitute values into the formula shown above and calculate the area, as following:

$K=\sqrt{63(63-33)(63-51)(63-42)}\\K=690.1units^{2}$

4. Therefore, the area is 690.1 units².

4 0

3 years ago

What is the converse of the following conditional statement? If x = –10, then x2 = 100

tangare [24]

The converse would be If x² = 100 then x = -10

So essentially if the conditional statement is p → q then the converse is q → p (In essence, the converse of a conditional statement is formed by interchanging the hypothesis and the conclusion.)

8 0

3 years ago

If log a=3 log b-2 log c, find an expression for a that does not involve logarithms

photoshop1234 [79]

Assuming that b>0 and c>0:

log(a)=3×log(b)-2×log(c)=

log(b³)-log(c²)=

log(b³/c²)

Hence a=b³/c²

7 0

3 years ago

The slope of the line is -3. Use the coordinates of the labeled point to find the point-slope equation of the line.

nekit [7.7K]

$m = \dfrac{Y_2 - Y_1}{X_2-X_1}$

$-3 = \dfrac{y + 7}{x - 5}$

$y + 7= -3(x - 5)$

Answer A

8 0

3 years ago

Read 2 more answers

30. What is the solution to the system of equations? (1 point)

sesenic [268]

Answer:

Option B) (-1,7,5) is correct.

The solution to the given system of equation is (-1,7,5)

Step-by-step explanation:

Given system of equations are

$-7x-2y+z=-2\hfill (1)$

$6x-y-z=-18\hfill (2)$

$5x+4y-z=18\hfill (3)$

To find the solution of the given system of equations by using Elimination method:

Now adding equations (1) and (2)

$-7x-2y+z=-2$

$6x-y-z=-18$

_________________

$-x-3y=-20$

________________

$-x-3y=-20$

$-(x+3y)=-20$

$x+3y=20\hfill (4)$ (since "-" getting cancelled)

Now adding equations (1) and (3)

$-7x-2y+z=-2$

$5x+4y-z=18$

_________________

$-2x+2y=16$

________________

$-2x+2y=16$

$2(-x+y)=16$

$-x+y=8\hfill (5)$

Now adding equations (4) and (5)

$x+3y=20$

$-x+y=8$

_________________

$4y=28$

________________

$y=\frac{28}{4}$

Therefore y=7

Substituting y=7 in equation (4)

$x+3y=20$

$x+3(7)=20$

$x+21=20$

$x=20-21$

Therefore x=-1

Now substituting the values x=-1 and y=7 in equation (1) we get

$-7x-2y+z=-2$

$-7(-1)-2(7)+z=-2$

$7-14+z=-2$

$z=-2+7$

Therefore z=5

Therefore the solution to the given system of equation is (-1,7,5)

Therefore Option B) (-1,7,5) is correct.

8 0

3 years ago