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deff fn [24]
4 years ago
5

Find the number of terms in the following sequence.

Mathematics
1 answer:
aleksklad [387]4 years ago
6 0

Answer:

<em><u>Oa</u></em><em><u>:</u></em><em><u> </u></em><em><u>1</u></em><em><u>4</u></em><em><u>1</u></em><em><u> </u></em><em><u>corre</u></em><em><u>ct</u></em><em><u> </u></em><em><u>option</u></em><em><u>!</u></em>

Step-by-step explanation:

33-(-9) =42

and 75-33= 42

clearly this is an Arithmetic progression with common difference=d=42

using (nth term = a+(n-1)d) {n is number of term,d is common difference and a is first term}

now, 5871 = -9+(n-1) 42

i.e, 5880=(n-1)42

i.e, n-1=140

i.e, n=141

✌️:)

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A line passes through the point with coordinates (0,8) and (3.-1). Which best describes the slope of the line?
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3 years ago
The floor function maps any humber to the greatest integer that is _[blank] the number.
wel

Answer:

Less Than or Equal to

Step-by-step explanation:

In mathematics and computer science, the floor and ceiling functions map a real number to the greatest preceding or the least succeeding integer, respectively. floor(x) : Returns the largest integer that is smaller than or equal to x (i.e : rounds downs the nearest integer).

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3 0
3 years ago
ABC is reflected across the x-axis and then translated 4 units up to create A' B' C'. What are the coordinates of the verticles
Andrei [34K]

Answer:  The co-ordinates of the vertices of triangle A'B'C' are A(-3, 3), B'(-1, 1) and C'(-2, 3).

Step-by-step explanation:  Given that the triangle ABC  is reflected across the x-axis and then translated 4 units up to create triangle A'B'C'.

We are to find the co-ordinates of the vertices of triangle A'B'C'.

From the figure, we note that

the co-ordinates of the vertices of triangle ABC are A(-3, 1), B(-1, 3) and C(-2, 1).

The reflection across X-axis changes the co-ordinates of a point according to the following rule :

(x, y) ⇒  (x, -y).

So, after reflecting across X-axis, the co-ordinates of the vertices of triangle ABC will become :

A(-3, 1)  ⇒  (-3, -1),

B(-1, 3)  ⇒  (-1, -3),

C(-2, 1)  ⇒  (-2, -1).

Now, translating a point 4 units up will change the co-ordinates as follows :

(x, y)  ⇒  (x, y+4).

Therefore, after translating the reflected triangle 4 units up, the fianl co-ordinates of triangle a'B'C' will become

(-3, -1)  ⇒  (-3, -1+4) = (-3, 3),

(-1, -3)  ⇒  (-1, -3+4) = (-1, 1),

(-2, -1)  ⇒  (-2, -1+4) = (-2, 3).

Thus, the co-ordinates of the vertices of triangle A'B'C' are A(-3, 3), B'(-1, 1) and C'(-2, 3).

3 0
4 years ago
Read 2 more answers
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