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timofeeve [1]
3 years ago
10

Find the value of x and y (i need this asap please)

Mathematics
1 answer:
disa [49]3 years ago
3 0
For a right triangle with 60° angle, and hypotenuse h=10√3,
x=h*sin(60)=10√ 3 * √3/2 = 30/2=15
y=h*cos(60)=10√3 * (1/2) = 5√3
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Larry has $150 in his bank account. He deposits $27 and then writes a check for $96
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A science test, which is worth 100 points, consists of 24 questions. Each question is worth either 3 points or 5 points. If x is
Maksim231197 [3]
X + y = 24....multiply by -3
3x + 5y = 100
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-3x - 3y = - 72 (result of multiplying by -3)
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If the inspection division of a county weights and measures department wants to estimate the mean amount of
Amanda [17]

If inspection department wants to estimate the mean amount with 95% confidence level with standard deviation 0.05 then it needed a sample size of 97.

Given 95% confidence level, standard deviation=0.05.

We know that margin of error is the range of values below and above the sample statistic in a confidence interval.

We assume that the values follow normal distribution. Normal distribution is a probability that is symmetric about the mean showing the data  near the mean are more frequent in occurence than data far from mean.

We know that margin of error for a confidence interval is given by:

Me=z/2* ST/\sqrt{N}

α=1-0.95=0.05

α/2=0.025

z with α/2=1.96 (using normal distribution table)

Solving for n using formula of margin of error.

n=(z/2ST/Me)^{2}

n=(1.96*0.05)^{2} /(0.01)^{2}

=96.4

By rounding off we will get 97.

Hence the sample size required will be 97.

Learn more about standard deviation at brainly.com/question/475676

#SPJ4

The given question is incomplete and the full question is as under:

If the inspection division of a county weights and measures department wants to estimate the mean amount of soft drink fill in 2 liters bottles to within (0.01 liter with 95% confidence and also assumes that standard deviation is 0.05 liter. What is the sample size needed?

7 0
2 years ago
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