Answer:
keiko- x
imelda- x+ 36
Sarah- x- 38
Step-by-step explanation:
- keiko is x since we have not been given his number of boxes.
- because imelda's number of boxes was 36 <em>more </em><em>than </em>keiko's, you will add the x which is for keiko and 36 for imelda(x+36).
- and sarah's number of boxes will be x-36 because we have been told her number of boxes is 38 <em>fewer </em><em>than </em> keiko's.
Answer:
3/4
Step-by-step explanation:
A: students present
B: students on time
P(all students present and on time) = P(A and B) = 3/10
P(all students present) = P(A) = 2/5
P(A and B) = P(A).P(B|A) where P(B|A) is the probability of everyone being on time given that everyone is present
So P(B|A) = P(A and B) /P(A) = 3/10 ÷ 2/5 = 3/10 * 5/2 = 15/20 which can be reduced to 3/4 by dividing numerator and denominator by 5
M-6 is the expression that shows how far Allison has to run
Answer:
5/36
Step-by-step explanation:
Dice 1 cannot be 1 no matter how large dice 2 gets
Dice 1 = 2,3,4,5,6 each matches with dice 2 to get a sum of 8