Answer:
66 ≤ f ≤100
Explanation
Mean= ( Σ x ) / n
Mean= sum of scores/ number of subject she took
Now, she already too 3 subject which sum is 85+83+86=254
Now we need to know range of score for her to have (grade) a mark between 80 and 89
Now let take the lower limit mean=80
The lowest score she can get is
Mean = ( Σx) / n
80=(85+83+86+f)/4
80×4= 254+f
Therefore, f= 320-254=66
Therefore the minimum score she can have to have a B is 66.
Then, let take the upper limit mean 89. i.e the maximum she can have so that she don't have an A grade.
Mean = ( Σx) / n
89=( 83+85+86+f)/4
89×4= 254+f
f= 356-254
f=102.
Therefore this shows that she cannot have an A grade in the exam. The maximum score for the exam is 100.
There the range of score is 66 ≤ f ≤100 to have a B grade
66 ≤ f ≤100 answer
Since she cannot score 102 in the examination.
(9+8+2)/(4+9+8+2)=19/23=82%
Therefore very likely
Answer: A is 36.82%. B is 35.5%
Step-by-step explanation: For manufacturer A 22/19 chian discount simply means 22% discount followed by 19% discount.
Therefore we have 100-22= 78 and 100-19=81.
The final price would be 0.78*0.81=0.6318
Therefore discount would be
1 - 0.6318=0.3682
Hence, percentage discount would be 0.3682*100%=36.82%.
For manufacturer B 25/14 chian discount means 25% discount followed by 14% discount. So we have 100-25=75% and 100-14= 86%
Final price would be 0.86*.75=0.645.
Discount= 1 - 0.645= 0.355.
Percentage discount would be 0.355*100%=35.5%.
<u>Answer:</u>
Range of this relation = -3, 2
<u>Step-by-step explanation:</u>
We are given the following relation and we are to find its range:
The set of all the possible dependent values a relation can produce from its values of domain are called its range. In simple words, it is the list of all possible inputs (without repeating any numbers).
Therefore, the range of this relation is: -3, 2
