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OlgaM077 [116]
3 years ago
10

You have $5. If candy bars cost $0.75, what is the greatest number of candy bars you can buy

Mathematics
2 answers:
mr_godi [17]3 years ago
5 0
You can buy six candy bars, hope this helped!

serg [7]3 years ago
5 0
You can buy 6 candy bars. and have 50 cents left over. 

6 candy bars will cost you $4.50 which fits your budget.
7 candy bars will cost you *5.25 which is over your budget.

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Please factorise the equations in the doc bellow ASAP. please show full working
ad-work [718]

Answer:

b. x² + 8x + 12 =

1. use the factoring X (see attachment)

2. 6 x 2 = 12; 6 + 2 = 12

3. (x + 6)(x + 2) = 0

4. x = -6, -2

c. x² + 13x + 12 =

1. 12 x 1 = 12; 12 + 1 = 13

2. (x + 12)(x + 1) = 0

3. x = -12, -1

c. x² + x - 12 =

1. 4 · (-3) = -12; 4 - 3 = 1

2. (x +4)(x - 3) = 0

3. x = -4, 3

f. x² + 15x + 36 =

1. 12 x 3 = 36; 12 + 3 = 15

2. (x + 12)(x + 3) = 0

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hope this helps :)

8 0
3 years ago
Read 2 more answers
What is the greatest common factor of theses variables
DerKrebs [107]
B is the answer!

Explanation:
m^2 n^2 fits into both, you can take m^2 n^2 out of it both.

m is a common factor since you can take m out of both but it’s not the greatest common factor.

2n & 2m wouldn’t even be a common factor bc there is no 2n or 2m in neither.
8 0
3 years ago
HELLO!! I NEED HELP! Please show full Solutions. I will mark brainliest for the best answer. Thank you and god bless.
Greeley [361]
((x+2)(x+2))-((x-5)(1))=A

x^2+4x+4-x+5=A

x^2+3x+9=A
8 0
3 years ago
Someone please help me, i’ve been stuck on this question and can’t figure it out.
kenny6666 [7]

Answer:

5/8

Step-by-step explanation:

the range is the largest number minus the smallest number so

1 1/4 - 5/8

5/4 - 5/8

you would take 5/4 *2 to get like denominators so,

10/8-5/8= 5/8

7 0
3 years ago
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10 points! How do I factor 8x^2-26x+15
Rufina [12.5K]
<h3><u>(2x - 5)(4x - 3)</u></h3>

The AC method, also known as splitting the middle, can be shown like this:

8x^2 - 26x + 15

<em><u>Check factors of 120.</u></em>

1 * 120

-1 * -120

2 * 60

-2 * -60

3 * 40

-3 * -40

5 * 24

-5 * -24

6 * 20

-6 * -20 (these factors, when added together, are equal to the middle term, and thus splitting the middle term is possible.)

<em><u>Split the middle term.</u></em>

8x^2 - 6x - 20x + 15

<em><u>Group in terms of 2.</u></em>

(8x^2 - 6x) - (20x + 15)

<em><u>Factor each binomial.</u></em>

2x(4x - 3) - 5(4x - 3)

<em><u>Rearrange the terms.</u></em>

(2x - 5)(4x - 3)

6 0
3 years ago
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