y = -3x - 2
Since a < 0 we have a decreasing line, so it can be only the first or the last
And if we solve the equation for y = 0 we have
0 = -3x - 2
3x = -2
x = -2/3
So, the last one is the right
1.7) < 7 and < 8 form a linear pair....which means, when added, they equal 180 degrees. So if < 7 = 61, then < 8 = (180 - 61) = 119 <=
1.8) angles that are supplementary will add up to 180. So if one of the angles is 38, then the other one is (180 - 38) = 142 <==
1.9) < 3 = < 5 (vertical angles are congruent)
1.10) < 2 = < 8 (vertical angles are congruent)
1.11) < 7 = < 1 (vertical angles)
1.12) < 6 = < 4 (vertical angles)
Hyp^2 = leg1^2 + leg2^2
hyp^2 -leg1^2 = leg2^2
17^2 - 8^2 = leg2^2
leg2^2 = 289 -64
leg2^2 = 225
leg2 = 15
Answer:
A line perpendicular to another has a slope that is the negative reciprocal of the slope of the other line. The negative reciprocal of the original line is –2, and is thus the slope of its perpendicular line.
Step-by-step explanation:
