Consider the exponential function f(x) = (15x). What is the value of the growth factor of the function
2 answers:
The growth rate is the a value, or the number before the x value. The answer would be 15.
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Step-by-step explanation:
Find equation
y - y1 = m(x - x1)
y + 9 = -5(x - 2)
y = -5x + 10 - 9
y = -5x + 1 → Equaton
You have a good day and good luck on that question
Answer:
Z: n = 1 P: n =80
Step-by-step explanation:
cross multiple what you can and divide it by the last number left to find n
![\bf \begin{cases} f(x)=\sqrt[3]{7x-2}\\\\ g(x)=\cfrac{x^3+2}{7} \end{cases}\\\\ -----------------------------\\\\ now \\\\ f[\ g(x)\ ]\implies f\left[ \frac{x^3+2}{7} \right]\implies \sqrt[3]{7\left[ \frac{x^3+2}{7} \right]-2}\implies \sqrt[3]{x^3+2-2} \\\\\\ \sqrt[3]{x^3}\implies x\\\\ -----------------------------\\\\ or \\\\ g[\ f(x)\ ]\implies g\left[\sqrt[3]{7x-2}\right]\implies \cfrac{\left[\sqrt[3]{7x-2}\right]^3+2}{7} \\\\\\ \cfrac{7x-2+2}{7}\implies \cfrac{7x}{7}\implies x](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%0Af%28x%29%3D%5Csqrt%5B3%5D%7B7x-2%7D%5C%5C%5C%5C%0Ag%28x%29%3D%5Ccfrac%7Bx%5E3%2B2%7D%7B7%7D%0A%5Cend%7Bcases%7D%5C%5C%5C%5C%0A-----------------------------%5C%5C%5C%5C%0Anow%0A%5C%5C%5C%5C%0Af%5B%5C%20g%28x%29%5C%20%5D%5Cimplies%20f%5Cleft%5B%20%5Cfrac%7Bx%5E3%2B2%7D%7B7%7D%20%5Cright%5D%5Cimplies%20%5Csqrt%5B3%5D%7B7%5Cleft%5B%20%5Cfrac%7Bx%5E3%2B2%7D%7B7%7D%20%5Cright%5D-2%7D%5Cimplies%20%5Csqrt%5B3%5D%7Bx%5E3%2B2-2%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Csqrt%5B3%5D%7Bx%5E3%7D%5Cimplies%20x%5C%5C%5C%5C%0A-----------------------------%5C%5C%5C%5C%0Aor%0A%5C%5C%5C%5C%0Ag%5B%5C%20f%28x%29%5C%20%5D%5Cimplies%20g%5Cleft%5B%5Csqrt%5B3%5D%7B7x-2%7D%5Cright%5D%5Cimplies%20%5Ccfrac%7B%5Cleft%5B%5Csqrt%5B3%5D%7B7x-2%7D%5Cright%5D%5E3%2B2%7D%7B7%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B7x-2%2B2%7D%7B7%7D%5Cimplies%20%5Ccfrac%7B7x%7D%7B7%7D%5Cimplies%20x)
thus f[ g(x) ] = x indeed, or g[ f(x) ] =x, thus they're indeed inverse of each other
I would say either 110 or 131 if I might be wrong so check with a protractor first.
