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3 years ago

PLEASE HELP!!

Mathematics

2 answers:

Dmitry [639]3 years ago

5 0

No intersection point, First choice

Anvisha [2.4K]3 years ago

4 0

Answer: First option is correct.

Step-by-step explanation:

Since we have given that

$x-y=1----------(1)\\\\y-x=1\\\\\implies x-y=-1-----------------(2)$

So, we first check its consistency:

$a_1=1,b_1=-1,c_1=1\\\\a_2=1,b_2=-1,c_2=-1$

So, $\frac{a_1}{a_2}=\frac{b_1}{b_2}\neq \frac{c_1}{c_2}\\\\\frac{1}{1}=\frac{1}{1}\neq \frac{1}{-1}\\\\1=1\neq -1$

So, it is the parallel lines.

Hence, there is no intersection points.

Therefore, First option is correct.

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Answer:

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Step-by-step explanation:

We have the following dataset given:

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We want to test the following hypothesis:

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And for this case we can find the critical value with the significance level $\alpha=0.05$ and if we find in the right tail of the z distribution we got:

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Replacing we got:

$z=\frac{0.344 -0.27}{\sqrt{\frac{0.27(1-0.27)}{125}}}=1.86$

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