Answer:
Explanation:
7. f(x) = x^4 + 3x^3 - 6x^2 - 10x + 8
f(2) = 2^4 + 2^3 - 6^2 - 10(2) + 8
f(2) = 16 + 8 - 12 - 20 + 8
f(2) = 0
8. x^2 - 9 = (x - 3)(x + 3)
x ^2 + x - 6 = (x + 3)(x -2)
Thus, the common factor is x + 3
Who says V1=V2?
if we simplify we get
(2/3)pir₁³=12pir₂²
for V1 to equal V2
a.
solve for r₁ to find r₁ as a function of r₂
(2/3)pir₁³=12pir₂²
times 3/2 both sides and divide by pi
r₁³=18r₂²
cube root both sides
r₁=∛(18r₂²)
if solve for r₂
(2/3)pir₁³=12pir₂²
divide by 12pi both sides
(1/18)r₁³=r₂²
squer root both sides
√((1/18)r₁³)=r₂
double radius of pond which is r1
√((1/18)r₁³)=r₂
r₁ turns to 2r₁ to double radius
√((1/18)(2r₁)³)=r₂double
√(8(1/18)(r₁)³)=r₂double
(√8)(√((1/18)(r₁)³))=r₂double
√((1/18)r₁³)=r₂ so
(√8)(r₂)=r₂double
(2√2)(r₂)=r₂double
the radius of the tank is multipled by 2√2
Answer:
Alice saved 218 and mindy saved 218+54
Step-by-step explanation:
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