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Taya2010 [7]
2 years ago
14

Suppose ABCD is a rectangle, F and G are points on

Mathematics
1 answer:
Elanso [62]2 years ago
3 0

The two sides are equal and for that reason DE = CE as shown below :

AD = BC, DF = GC

E = A(F) and E = BG,  therefore A(F) = BF

<h3>Description of rectangle</h3>

Now we all know that a rectangle has four edges which are A, B, C, D.

when we divide the bottom line, which is the line from point C to D into three parts we will have ( DF, FG, and GC )

From the question we know that DF = GC

E is the intersection of A(F) and BG

we can now Prove that DE = CE.

since D and C are point included in E and since this is a rectangle

AD = BC, DF = GC

E = A(F) and E = BG,  therefore A(F) = BF

DE = CE

We can conclude by saying that in a rectangle two sides are equal and for that reason DE = CE

Learn more about Rectangle : brainly.com/question/22148953

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If Connie spent $26 on 8 books, The number of hard covers she buy is 5 hard cover.

<h3>Number of hardcover bought</h3>

Let h represent hard cover

Let p represent paperbacks

Formulate an equation

h + p= 8.......(1)

4h + 2p= 26......(2)

Multiply equation (1) by -2

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Therefore If Connie spent $26 on 8 books, The number of hard covers she buy is 5 hard cover.

Learn more about Number of hardcover bought here:brainly.com/question/18306224

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