Answer:
Step-by-step explanation:
I'm sure you want your functions to appear as perfectly formed as possible so that others can help you. f(x) = 4(2)x should be written with the " ^ " sign to denote exponentation: f(x) = 4(2)^x
f(b) - f(a)
The formula for "average rate of change" is a.r.c. = --------------
b - a
change in function value
This is equivalent to ---------------------------------------
change in x value
For Section A: x changes from 1 to 2 and the function changes from 4(2)^1 to 4(2)^2: 8 to 16. Thus, "change in function value" is 8 for a 1-unit change in x from 1 to 2. Thus, in this Section, the a.r.c. is:
8
------ = 8 units (Section A)
1
Section B: x changes from 3 to 4, a net change of 1 unit: f(x) changes from
4(2)^3 to 4(2)^4, or 32 to 256, a net change of 224 units. Thus, the a.r.c. is
224 units
----------------- = 224 units (Section B)
1 unit
The a.r.c for Section B is 28 times greater than the a.r.c. for Section A.
This change in outcome is so great because the function f(x) is an exponential function; as x increases in unit steps, the function increases much faster (we say "exponentially").
Answer:
C. 2
Step-by-step explanation:
h/6 + h/3 = 1
h/6 + 2h/6 = 1
3h/6 = 1
3h = 6
h = 2
Answer:
x = 
Step-by-step explanation:
Given
+ 
= 1
Multiply through by ab to clear the fractions
bx + ax = ab ← factor out x from each term on the left side
x(b + a) = ab ← divide both sides by (b + a)
x =
Step-by-step explanation:
Erase the dot points you already have. We are supposed to substitute those values in the right side of problem 1 into the function as x.
For example if x=-4
If x=-2
If x=0
So our point should be
-4,9
-2,7
0,5
-2,3
-4,1.
The range is all possible y values in a function. Since this is discrete and we are given the domain, our range will just be the y value of the points you graphed.
(9,7,5,3,1)
Answer:
x + 3y = 15
Step-by-step explanation:
Line is passing through the points 
Slope of line (m)= (2 - 4)/(9 - 3) = -2/6 = -1/3
Equation of line in point-slope form is given as:
Plugging the values of 
in the above equation we find:
This is the required equation of line in the form 
