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2 years ago

David says,

Mathematics

1 answer:

Softa [21]2 years ago

5 0

Answer:

no, 72 km/hr is equal to 20m per sec

Step-by-step explanation:

20 m = .02 km

.02 km per hour is equal to .02(3600) per hour, which is 72 km per hour

(you have to multiply my 3600 to get seconds into hours)

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3. Fine the value of x. <br> A) 3.5<br> B)7<br> C) 5<br> D)10

Rom4ik [11]

Answer:

I would say B

Step-by-step explanation:

I think

5 0

2 years ago

Read 2 more answers

Find the value of x.

mixas84 [53]

Answer:

x=3

Step-by-step explanation:

BRAINLIEST plzzzzzzzzzzzzzzzzzz

8 0

2 years ago

hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and

Mariulka [41]

Given:

The equation is,

$2\log _3x-\log _3(x-2)=2$

Explanation:

Simplify the equation by using logarthimic property.

$\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{ \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}$

Simplify further.

$\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}$

Solve the quadratic equation for x.

$\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}$

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

$\begin{gathered} x-6=0 \\ x=6 \end{gathered}$

For (x - 3) = 0,

$\begin{gathered} x-3=0 \\ x=3 \end{gathered}$

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

$\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}$

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

$\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}$

Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

6 0

10 months ago

Find the distance and the midpoint of the line segment with endpoints (-1,4) and (-5,3)

Marina CMI [18]

Answer:

see explanation

Step-by-step explanation:

Calculate the distance (d) using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (- 1,4) and (x₂, y₂ ) = (- 5, 3)

d = $\sqrt{(-5+1)^2+(3-4)^2}$

= $\sqrt{(-4)^2+(-1)^2}$

= $\sqrt{16+1}$ = $\sqrt{17}$ ≈4.12 ( to 2 dec. places )

To find the midpoint use the midpoint formula

[0.5(x₁ + x₂ ), 0.5(y₁ + y₂ ) ]

Using the same points as above then

midpoint = [0.5(- 1- 5), 0.5(4 + 3 ) ] = [0.5(- 6), 0.5(7) ] = (- 3, 3.5 )

4 0

3 years ago

Pls help me ill give brainliest and no links ty!<3:)

Neko [114]

T is the midpoint of PQ

PT=TQ

5x+7 = 7x-7

2x= 14

x= 14/2

x= 7

PT = 5(7)+7 = 42

5 0

2 years ago