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slega [8]
3 years ago
10

Trisha needs to make at least 50 gift bags for an event. Each gift bag will contain at least 1 thumb drive or 1 key chain. She w

ants to use at least 5 times as many key chains as thumb drives. She has 25 thumb drives and 200 key chains.
Let x represent the number of key chains. Let y represent the number of thumb drives.

Which inequalities are among the constraints for this situation?

Select each correct answer.




x+y≥50

x≥5y

x≤5y

x+5y≤50

y≤25

Mathematics
2 answers:
mel-nik [20]3 years ago
8 0

Answer:

y ≤ 25

x ≥ 5y

x + y ≥ 50

Step-by-step explanation:

Archy [21]3 years ago
6 0

Answer:I Believe the Correct answers are:

x+5y ≤ 50

and

x+y≥50



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How to figure it out
harkovskaia [24]
Have
.5x+.10y+.20z=380
8 0
3 years ago
The graph h = −16t^2 + 25t + 5 models the height and time of a ball that was thrown off of a building where h is the height in f
Thepotemich [5.8K]

Answer:

part 1) 0.78 seconds

part 2) 1.74 seconds

Step-by-step explanation:

step 1

At about what time did the ball reach the maximum?

Let

h ----> the height of a ball in feet

t ---> the time in seconds

we have

h(t)=-16t^{2}+25t+5

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

so

The x-coordinate of the vertex represent the time when the ball reach the maximum

Find the vertex

Convert the equation in vertex form

Factor -16

h(t)=-16(t^{2}-\frac{25}{16}t)+5

Complete the square

h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+5+\frac{625}{64}

h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}\\h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}

Rewrite as perfect squares

h(t)=-16(t-\frac{25}{32})^{2}+\frac{945}{64}

The vertex is the point (\frac{25}{32},\frac{945}{64})

therefore

The time when the ball reach the maximum is 25/32 sec or 0.78 sec

step 2

At about what time did the ball reach the minimum?

we know that

The ball reach the minimum when the the ball reach the ground (h=0)

For h=0

0=-16(t-\frac{25}{32})^{2}+\frac{945}{64}

16(t-\frac{25}{32})^{2}=\frac{945}{64}

(t-\frac{25}{32})^{2}=\frac{945}{1,024}

square root both sides

(t-\frac{25}{32})=\pm\frac{\sqrt{945}}{32}

t=\pm\frac{\sqrt{945}}{32}+\frac{25}{32}

the positive value is

t=\frac{\sqrt{945}}{32}+\frac{25}{32}=1.74\ sec

8 0
3 years ago
Please huryy!!
ArbitrLikvidat [17]

Answer:

1.5

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Is #1 correct and I need help on #2 THANKS :)
horsena [70]
Answer 1 = I believe you are correct cause when doing area , remembering you times the different area of the sides


Answer 2 = I believe the answer is C (2,0009) cause remember adding when doing volume but there are few steps ..
. i have done the work for this and hoping my work helped the answer i got help you! comment below if you need anything , thanks , have a nice day!!
6 0
3 years ago
PLEASE ANSWER ASAP FOR BRAINLEST WITH WORK!!!!!!!!!!!!!!!
alexira [117]

Answer:

The answer is 43 because 600/14 = 42.8571429 rounded to the nearest whole number is 43.

Step-by-step explanation:

4 0
3 years ago
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