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Rudiy27
1 year ago
9

The table shows information about the masses of some dogs. a) Work out the minimum number of dogs that could have a mass of more

than 27 kg. b) Work out the maximum number of dogs that could have a mass of more than 27 kg. Mass, x (kg) 0≤x≤10 10≤x≤20 20≤x≤30 30≤x≤40 Frequency 3 9 13 4
​

Mathematics
1 answer:
V125BC [204]1 year ago
6 0

Information regarding various dogs' masses is displayed in the table.

(a) 4 bare minimum number of dogs that could weigh more than 27 kg.

(b) 17 dogs, in total, may weigh more than 27 kg.

Given that,

Information regarding various dogs' masses is displayed in the table.

(a)Calculate the bare minimum number of dogs that could weigh more than 27 kg.

(b)Calculate how many dogs, in total, may weigh more than 27 kg.

(a) 4 bare minimum of dogs that could weigh more than 27 kg.

Because the minimum number so lets assume that all dogs in 20≤x<30 are less then 27.

Therefore, 4 bare minimum of dogs that could weigh more than 27 kg.

(b) 17 dogs, in total, may weigh more than 27 kg.

Because the maximum number so lets assume that all dogs in 20≤x<30 are more then 27.

4+13=17

Therefore,17 dogs, in total, may weigh more than 27 kg.

To learn more about numbers visit: brainly.com/question/17429689

#SPJ1

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1. x=22/5
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3 years ago
45/19 as a decimal rounded to the nearest tenth
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Answer:

Step-by-step explanation:

45/19 ~ 2.4

Hope that helps!

8 0
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The smith family walked 2/3 of a mile in 2/7 of an hour? What is their unit rate in miles per hour? Explain how this is determin
frez [133]

Answer: 2\dfrac13\text{ miles per hour}

Step-by-step explanation:

Given: Distance traveled by Smith = \dfrac23 mile.

Time taken = \dfrac27  hour

Unit rate in miles per hour = ( Distance traveled by Smith) ÷ (Time taken)

=\dfrac23\div\dfrac27

\\\\=\dfrac23\times\dfrac72\\\\=\dfrac73\\\\=2\dfrac13\text{ miles per hour}

Unit rate  = 2\dfrac13\text{ miles per hour}

6 0
3 years ago
Mai wants to make a scale drawing of her kitchen. Her kitchen is a rectangle with length 6 m and width 2 m. She decides on a sca
BigorU [14]

Answer:

Length of scale = 15 cm

Width of scale = 5 cm

Step-by-step explanation:

Dimensions of the kitchen of Mai are given as:

Length of kitchen = 6 m

Width of kitchen = 2 m

Scale to be used = 1 to 40

To find:

The drawing with labeling and dimensions of the scale drawing.

Solution:

First of all, let us understand about the concept of scaling.

Scaling is a method to represent big structures on paper.

For this purpose, we decide a scaling factor and draw the big structures on paper by scaling down (making it small) by using a scaling factor.

Here, the scale factor used is 1 to 40.

i.e. 1 unit on scale is equivalent to 40 units on the actual kitchen.

40 units of kitchen = 1 unit of scale

1 unit of kitchen = \frac{1}{40} units of scale

6 m of kitchen = \frac{1}{40}\times 6\ m = \frac{600}{40}\ cm = 15\ cm

Length of scale = <em>15 cm</em>

40 units of kitchen = 1 unit of scale

1 unit of kitchen = \frac{1}{40} units of scale

2 m of kitchen = \frac{1}{40}\times 2\ m = \frac{200}{40}\ cm = 5\ cm

Width of scale = <em>5 cm</em>

<em></em>

Please refer to the attached image as well for representation of given scale.

4 0
3 years ago
1. In order to get more female customers, a new clothing store offers free gourmet coffee and pastry to its customers. The avera
ioda

Answer:

No, the manager is not correct based on the 95% confidence interval.

Step-by-step explanation:

We are given that the average daily revenue over the past five-week period has been $1,080 with a standard deviation of $260, i.e.; X bar = $1080 and s = $260 and sample size, n = 35 .

The Pivotal quantity for 95% confidence interval is given by;

                \frac{Xbar - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = $1080

                s  = sample standard deviation = $260

                 n = sample size = 35 {five-week}

So, 95% confidence interval for average daily revenue, \mu is given by;

P(-2.032 < t_3_4 < 2.032) = 0.95

P(-2.032 < \frac{Xbar - \mu}{\frac{s}{\sqrt{n} } } < 2.032) = 0.95

P(-2.032 * {\frac{s}{\sqrt{n} } < {Xbar - \mu} < 2.032 * {\frac{s}{\sqrt{n} } ) = 0.95

P(X bar - 2.032 * {\frac{s}{\sqrt{n} } < \mu < X bar + 2.032 * {\frac{s}{\sqrt{n} } ) = 0.95

95% confidence interval for \mu = [ X bar - 2.032 * {\frac{s}{\sqrt{n} } , X bar + 2.032 * {\frac{s}{\sqrt{n} } ]

                                            = [ 1080 - 2.032 * {\frac{260}{\sqrt{35} } , 1080 + 2.032 * {\frac{260}{\sqrt{35} } ]

                                             = [ 990.70 , 1169.30 ]

<em>No, the manager is not correct based on the fact that the coffee and pastry strategy would lead to an average daily revenue of $1,200 because the calculate 95% confidence interval does not include value of $1200.</em>

Therefore, the store manager believe is not correct.

8 0
3 years ago
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