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Rudiy27
1 year ago
9

The table shows information about the masses of some dogs. a) Work out the minimum number of dogs that could have a mass of more

than 27 kg. b) Work out the maximum number of dogs that could have a mass of more than 27 kg. Mass, x (kg) 0≤x≤10 10≤x≤20 20≤x≤30 30≤x≤40 Frequency 3 9 13 4
​

Mathematics
1 answer:
V125BC [204]1 year ago
6 0

Information regarding various dogs' masses is displayed in the table.

(a) 4 bare minimum number of dogs that could weigh more than 27 kg.

(b) 17 dogs, in total, may weigh more than 27 kg.

Given that,

Information regarding various dogs' masses is displayed in the table.

(a)Calculate the bare minimum number of dogs that could weigh more than 27 kg.

(b)Calculate how many dogs, in total, may weigh more than 27 kg.

(a) 4 bare minimum of dogs that could weigh more than 27 kg.

Because the minimum number so lets assume that all dogs in 20≤x<30 are less then 27.

Therefore, 4 bare minimum of dogs that could weigh more than 27 kg.

(b) 17 dogs, in total, may weigh more than 27 kg.

Because the maximum number so lets assume that all dogs in 20≤x<30 are more then 27.

4+13=17

Therefore,17 dogs, in total, may weigh more than 27 kg.

To learn more about numbers visit: brainly.com/question/17429689

#SPJ1

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2x^2+7x=15 write in standard then factor the left side of the equation.
Nataly [62]

Answer:

see explanation

Step-by-step explanation:

Given

2x² + 7x = 15 ( subtract 15 from both sides )

2x² + 7x - 15 = 0 ← in standard form

To factorise the left side

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 2 × - 15 = - 30 and sum = + 7

The factors are + 10 and - 3

Use these factors to split the x- term

2x² + 10x - 3x - 15 ( factor the first/second and third/fourth terms )

2x(x + 5) - 3(x + 5) ← factor out (x + 5) from each term

(x + 5)(2x - 3) ← in factored form

5 0
3 years ago
Kyle soles 18 of 24 puzzles in a puzzle book. he says that he can use an equivalent fraction to find the percent of puzzles in t
tino4ka555 [31]

Answer:

He solved 75% of the puzzles!

Step-by-step explanation:

Okay, let's look at our fraction 18 out of 24. We can see that they are both even numbers, so at worst, we can divide the entire fraction by two. However, they have a GCF of six, so we will use that.

18                               3

----  divided by 6  =  ----

24                              4

Now that we have the fraction 3/4, we can turn that into a percentage!

3/4 is 0.75. To get the percentage, we multiply that by 100--now we have 75%.

5 0
3 years ago
4 1/12 + 1 3/4 = ?<br> Fractions please help I'm tired.
AfilCa [17]

Lets just convert them into improper fractions.

1) 4 and 1/12 = 49/12.

1 and 3/4 = 7/4.

2) 7/4 = 21/12

3) 21/12 + 49/12 = 70/12

Back to mixed fractions!

70/12 = 5 and 10/12 = 5 and 5/6

=5 5/6

⭐ Answered by Foxzy0⭐

⭐ Brainliest would be appreciated, I'm trying to reach genius! ⭐

⭐ If you have questions, leave a comment, I'm happy to help! ⭐

There is another method if you want to know. You can simply just do 4 + 1 = 5. Then do 1/12 + 3/4 = 10/12 = 5/6. So it goes to 5 5/6. Your choice which ever you find more eas.

7 0
2 years ago
Read 2 more answers
Help me please nobody seems to help me :(
podryga [215]

Answer:

A: (4, -2)

B: (-3, -3)

C: (-2, 5)

D: (-3, -3)

E: (1, -4)

F: (0, 3)

6. Option B

Step-by-step explanation:

5 0
3 years ago
An alloy of tin is 15% tin and weights 20 pounds. A second allow is 10% tin. How many pounds of the second alloy must be added t
Fofino [41]
Let x represent the amount to be added. The total amount of tin will be
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  (15%-12%)·20 = (12%-10%)·x
  3%·20/2% = x
  30 = x

30 pounds of 10% tin must be added to get a 12% mixture.
8 0
2 years ago
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