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andreyandreev [35.5K]
3 years ago
12

A hemispherical bowl of radius 5 inches is filled to a depth of h​ inches, where 0less than or equalshless than or equals5. Find

the volume of water in the bowl as a function of h.​ (check the special cases hequals0 and hequals5​.)
Mathematics
1 answer:
mestny [16]3 years ago
4 0

The shape of the water is that of a "spherical cap." The formula for the volume of a spherical cap is ...

... V = π·h²·(r -h/3) . . . . . . . from web search

For a radius of 5 in, this is

... V = π·h²·(5 -h/3) . . . . in³

_____

For h=0

... V = π·0²·(5 -0/3) = 0

For h=5 in

... V = π·(5 in)²·((5 -5/3) in) = (2/3)π·5³ in³ . . . . . the volume of a hemisphere of radius 5

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Sample annual salaries (in thousands of dollars) for employees at a company are listed. 42 36 48 51 39 39 42 36 48 33 39 42 45 (
Sonja [21]

Answer:

a) Data given: 42 36 48 51 39 39 42 36 48 33 39 42 45

\bar X = 41.538

s = 5.317

b) 44.1, 37.8, 50.4, 53.55, 40.95, 44.1, 37.8, 50.4 ,34.65, 40.95, 44.1, 47.25

\bar X = 43.615

s= 5.583

c) 3.5, 3, 4, 4.25, 3.25, 3.25, 3.5, 3, 4, 2.75, 3.25, 3.5, 3.75

\bar X= 3.462

s = 0.443

d) As we can see, the average of part b is 1.05 times the average of part a (1.05 * 41.538 = 43.615) and the average of part c is equal to the average obtained in part a divided by 12 (41.538 / 12 = 3.462).

And that happens because we create linear transformations for the parts b and c and the linear transformation affects the mean.

And you have the same interpretation for the deviation, it is affected by the linear transformation as the mean.

Step-by-step explanation:

For this case we can use the following formulas for the mean and standard deviation:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Part a

Data given: 42 36 48 51 39 39 42 36 48 33 39 42 45

And if we calculate the mean we got:

\bar X = 41.538

s = 5.317

Part b

For this case we know that each value present a 5% of rise so we just need to multiply each value bu 1.05 and we have this new dataset:

44.1, 37.8, 50.4, 53.55, 40.95, 44.1, 37.8, 50.4 ,34.65, 40.95, 44.1, 47.25

And if we calculate the new mean and deviation we got:

\bar X = 43.615

s= 5.583

Part c

The new dataset would be each value divided by 12 so we have:

3.5, 3, 4, 4.25, 3.25, 3.25, 3.5, 3, 4, 2.75, 3.25, 3.5, 3.75

And the new mean and deviation would be:

\bar X= 3.462

s = 0.443

Part d

As we can see, the average of part b is 1.05 times the average of part a (1.05 * 41.538 = 43.615) and the average of part c is equal to the average obtained in part a divided by 12 (41.538 / 12 = 3,462).

And that happens because we create linear transformations for the parts b and c and the linear transformation affects the mean.

And you have the same interpretation for the deviation, it is affected by the linear transformation as the mean.

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Elementary school students spend 1/6 of their day at recess on average. If they are in school 6 1/2 hours a day, how much time i
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Answer:

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Answer:

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"sum of 2 and 5 is divided by the difference of 9 and 4"

= (2 + 5) / (9 - 4)

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