Answer:
300
Step-by-step explanation:
Because of PEMDAS (Order of Operations), you would do the exponent first.
So, 3(x)^2 and 3(100)
Then you get 300
Hope this helps!
Solution -
drawing a perpendicular from AQ to TS, we get a right angle triangle AQT
Using Pythagoras Theorem,
AT² = AQ² + QT²
⇒26² = 24² + QT² (∵ Due to symmetry AQ = RS)
⇒QT² = 676-576 = 100
⇒QT = 10
As TS = QT + QS = 12 + 10 = 22 ( ∵ Due to symmetry AR = QS )
∴ TS = 22 (ans)
Answer:
It's +2
Step-by-step explanation:
As the positive occurs on the right side of the negatives in the number line so if we keep extending on the right side so we get +2
Answer:
G
Step-by-step explanation:
you know its G just by the way it is
Using the Factor Theorem, it is found that yes, it is possible for a sixth degree polynomial function with integer coefficients to have no real zeroes, as they can have three complex-conjugate pairs.
<h3>What is the Factor Theorem?</h3>
The Factor Theorem states that a polynomial function with roots
is given by:
![f(x) = a(x - x_1)(x - x_2) \cdots (x - x_n)](https://tex.z-dn.net/?f=f%28x%29%20%3D%20a%28x%20-%20x_1%29%28x%20-%20x_2%29%20%5Ccdots%20%28x%20-%20x_n%29)
In which a is the leading coefficient.
If a complex number is a root of a function, it's conjugate will also be a root. Thus, with three pairs of complex-conjugate roots, for example,
, a sixth degree function with no real zeros is formed, so the answer is Yes.
More can be learned about the Factor Theorem at brainly.com/question/24380382