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MissTica
2 years ago
15

I need help with Geometry

Mathematics
2 answers:
romanna [79]2 years ago
8 0

Answer:

No, the values need to add to 360

Step-by-step explanation:

Andrej [43]2 years ago
6 0

Answer:

no because thats an obtuse angle and there has to be an acute triangle to from a triangle so no

Step-by-step explanation:

You might be interested in
A number is 6.14 what way represent the value of the 4 in 6.14
Lady_Fox [76]

Answer:

Step-by-step explanation:

the value of the 4 in 6.14 is 0.04.

this is because the 4, or in this case 0.04

is in the hundredths place. So it is

suppose to have 0, where the 6 goes (also

the ones or units) The decimal point, another 0

where the 1 goes, ( the tenths) and finally back

to the 4. (Like I said, it’s the hundredths place)

so there you have it. Your answer will be 0.04

5 0
3 years ago
Pls help me with this
katovenus [111]

Answer:

5.85

Step-by-step explanation:

100%-> 6.50

100%-10% = 90 %

90%-> 6.50/100 x 90

           =5.85

8 0
2 years ago
4/5 • 6 = x <br> What is x?
Savatey [412]
X= 4.8 or x= 4 4/5 i believed
8 0
2 years ago
On a coordinate plane, rhombus W X Y Z is shown. Point W is at (7, 2), point X is at (5, negative 1), point Y is at (3, 2), and
Otrada [13]

Answer:

P = 4\sqrt{13}

Step-by-step explanation:

Given

W = (7, 2)

X = (5, -1)

Y = (3, 2)

Z =(5, 5)

Required

The perimeter

To do this, we first calculate the side lengths using distance formula

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2

So, we have:

WX = \sqrt{(5- 7)^2 + (-1 - 2)^2

WX = \sqrt{13}

XY = \sqrt{(3-5)^2 + (2--1)^2}

XY = \sqrt{13}

YZ = \sqrt{(5-3)^2 + (5-2)^2}

YZ = \sqrt{13}

ZW = \sqrt{(7 - 5)^2 + (2 - 5)^2}

ZW = \sqrt{13}

The perimeter is:

P = WX + XY + YZ + ZW

P = \sqrt{13}+\sqrt{13}+\sqrt{13}+\sqrt{13}

P = 4\sqrt{13}

5 0
3 years ago
Read 2 more answers
After jumping rope for 15 minutes, Jan took a break. If Jan took a break at 3:05 p.M., at what time did she start jumping rope?
Kitty [74]

Answer: 2 : 50 pm

Step-by-step explanation:

If Jan took a break at 3:05 pm and she had been jumping rope for 15 minutes before that, to find the time she started jumping rope, subtract 15 from the current time:

= 3:05 - 15

= 2:50 pm

<em>Jan started jumping rope at 2 : 50 pm </em>

3 0
3 years ago
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