Answer:
I got 1.75 too
Step-by-step explanation:
20/3.5 is 5.7
10/5.7 is 1.75
11 9/10 First you have to add 10 3/5 and 12 1/2. You get 22 11/10. That is an improper fraction. There are one 10 in 11. So you add 1 1/10 to 22. You get 23 1/10. Now you have to subtract 23 1/10 and 35. You get 11 9/10
Answer:
The answer is: 13 minutes
Step-by-step explanation:
First Let us form equations with the statements in the two scenario
Let the time in which the bell rings be 'x'
1. If Andrew walks (50 meters/minute), he arrives 3 minutes after the bell rings. Therefore the time of arrival at this speed = (3 + x) minutes
2. If Andrew runs (80 meters/minute), he arrives 3 minutes before the bell rings. Therefore the time taken to travel the distance = (x - 3) minutes

In both cases, the same distance is travelled, therefore, equation (1) = equation (2)

Next, collecting like terms:

dividing both sides by 3:
x = 390÷30 = 13
∴ x = 13 minutes
Answer:
Step-by-step explanation:
really
12x+-4y=34x
Answer:
44.18 cubic unit
Step-by-step explanation:
The intersection of the curve
and
is




Since we are rotating the region where
we will use the intersection x = 2 and y = 4
Using the shell method with x ranges from 0.5 to 2. The volume of the shell would be

where h is the difference between the y-coordinates of the curves, in other words

Plug h into the V integral and we have
![V = \int\limits^2_{0.5} {2\pi x (8 - 2x^2)} \, dx\\V = 4\pi\int\limits^2_{0.5} {(4x - x^3)} \, dx\\V = 4\pi[2x^2 - x^4/4]^2_{0.5}\\V = 4\pi(2*2^2 - 2^4/4 - 2*0.5^2 + 0.5^4/4)\\V = 4\pi(8 - 4 - 0.5 + 0.015625) \approx 44.18](https://tex.z-dn.net/?f=V%20%3D%20%5Cint%5Climits%5E2_%7B0.5%7D%20%7B2%5Cpi%20x%20%288%20-%202x%5E2%29%7D%20%5C%2C%20dx%5C%5CV%20%3D%204%5Cpi%5Cint%5Climits%5E2_%7B0.5%7D%20%7B%284x%20-%20x%5E3%29%7D%20%5C%2C%20dx%5C%5CV%20%3D%204%5Cpi%5B2x%5E2%20-%20x%5E4%2F4%5D%5E2_%7B0.5%7D%5C%5CV%20%3D%204%5Cpi%282%2A2%5E2%20-%202%5E4%2F4%20-%202%2A0.5%5E2%20%2B%200.5%5E4%2F4%29%5C%5CV%20%3D%204%5Cpi%288%20-%204%20-%200.5%20%2B%200.015625%29%20%5Capprox%2044.18)