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Sav [38]
3 years ago
15

Write an equation in slope intercept form for the graph below

Mathematics
1 answer:
labwork [276]3 years ago
8 0

Answer:

y = 10x

Step-by-step explanation:

Finding the slope (m) of the line the following points in the line, (0, 0) and (2, 20):

slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{20 - 0}{2 - 0} = \frac{20}{2} = 10

y-intercept (b) is 0. The line intercepts the y-axis at 0. Thus, b = 0.

Substitute m = 10 and b = 0 in y = mx + b

The equation in slope-intercept form for the graph would be:

✅y = 1x + 0

y = 10x

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Y = x^3 + 5x^2 + 3x x= -3
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Answer:

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Step-by-step explanation:

-3^3 +5*(3)^2 +3*-3

-27+5*9+(-9)

-27+45-9

=9

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Answer:

c=9

Step-by-step explanation

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3 years ago
Someone please help me with these 2 problems :(
k0ka [10]
If the discriminant b^2-4ac is 0, then you have TWO EQUAL, REAL ROOTS.

If you're given the x-intercepts, you can determine the factors of the polynomial as follows:   Take -3, change the sign and write (x+3).  Take 5, change the sign and write (x-5).  Then the eq'n of the parabola is

f(x) = (x+3)(x-5) = x^2 - 2x -15, in which a=1, b = -2 and c= -15.

You can find the x-coordinate of the vertex, which is also the equation of the axis of symmetry, using

x= -b / (2a).    Here, x = -(-2) / (2[1]), or  x = 1

Find the y-coordinate by subbing 1 for x in the equation above:

y = (1)^2 - 2(1) - 15  =  1 - 2 - 15  =  -16

The vertex is at (1, -16) and the equation of the axis of symm. is x = 1.
7 0
3 years ago
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