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Mice21 [21]
2 years ago
8

Write an equation to model growth or decay in the following scenario. A stock is declining at a rate of 25% of its value every 2

weeks. The stock started at $225. Let a represent the number of weeks. Let y represent the value of the stock in dollars.
​
Mathematics
1 answer:
yawa3891 [41]2 years ago
3 0

The exponential function that models this situation is:

y(t) = 225(0.75)^{\frac{t}{2}}

------------------------------------------

A decaying exponential function has the following format:

y(t) = y(0)(1 - r)^t

In which:

  • y(0) is the initial value.
  • r is the decay rate, as a decimal.

In this problem:

  • The stock started at $225, thus y(0) = 225.
  • Declines at a rate of 25% every 2 weeks, thus r = 0.25, t = \frac{t}{2}

The equation is:

y(t) = y(0)(1 - r)^t

y(t) = 225(1 - 0.25)^{\frac{t}{2}}

y(t) = 225(0.75)^{\frac{t}{2}}

A similar problem is given at brainly.com/question/24282972

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The number of retro portable CD players you are prepared to supply to a retail outlet every week is given by the formula q = 0.2
krok68 [10]

Answer:

Decreasing by 30 per week

Step-by-step explanation:

q = 0.2p^2 + 2p

\frac{dq}{dt}=0.4p \frac{dp}{dt} + 2\frac{dp}{dt}

\frac{dq}{dt}=(0.4p + 2)\frac{dp}{dt}

At p=70,  \frac{dp}{dt}=-1

\frac{dq}{dt}=(0.4X70 + 2)(-1)

\frac{dq}{dt}=-30

The number supplied is decreasing by 30 per week.

4 0
3 years ago
The seat of a bench is in the shape of a trapezoid with bases of 6 feet and 3 feet and a
slavikrds [6]

Answer:

6.75 ft^2

Step-by-step explanation:

The area of the seat can be calculated as follows

a + b/2 × h

6+3/2 × 1.5

9/2 × 1.5

4.5× 1.5

= 6.75 ft^2

Hence the area of the seat is 6.75ft^2

5 0
3 years ago
To find the quotient 3/4 ÷ 1/8
klio [65]
Either b or a sorry if wrong
5 0
3 years ago
An airplane took 2 hours to fly 600 km against a head wind. The retrun trip with the wind took 1 and two thirds hours. Find the
Agata [3.3K]

Answer:

The speed of plane in still air is 330 kmph  

Step-by-step explanation:

Given as :

The distance cover against the wind = 600 km

The time taken against the wind = 2 hours

The distance cover with the wind = 600 km

The time taken with the wind =  ( 1 + \frac{2}{3} ) hours

                                                =  \frac{5}{3} hours

Let The speed against the wind  = x - y  kmph

The speed with the wind = x + y  kmph

where x is the speed of plane in still air

And y is the speed of wind

So , Speed = \dfrac{\texrm Distance}{\texrm Time}

Or, x - y = \frac{600}{2} = 300         ......A

And x + y = \frac{600}{\frac{5}{3} }

Or , x + y = 360                                                 .......B

From eq A and B

( x + y ) - ( x - y ) = 360 - 300

Or, 2 y = 60

∴  y = \frac{60}{2} = 30  kmph

And x = 360 - 30 = 330  kmph

Hence The speed of plane in still air is 330 kmph   Answer

3 0
3 years ago
On a piece of paper, use a protractor to construct △ABC with m∠A=30° , m∠B=60° , and m∠C=90° .
siniylev [52]
The answer is BC < AC and BC < AB

I just did the test this right right.
hope I helped.

4 0
3 years ago
Read 2 more answers
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