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alexgriva [62]
3 years ago
10

Find the point of the intersection for the given systems y=x^2+1 and y=x+1

Mathematics
1 answer:
mario62 [17]3 years ago
7 0

set them equal to each other

x²+1=x+1

minus 1 from both sides

x²=x

minus x both sides

x²-x=0

factor

x(x-1)=0

set each to 0

x=0


x-1=0

x=1


subsitute back to find y values

y=x+1, y=0+1, y=1, one point is (0,1)

y=x+1, y=1+1, y=2, another point is (1,2)


the 2 points of intersection are (0,1) and (1,2)

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A company compiles data on a variety of issues in education. In 2004 the company reported that the national college​ freshman-to
nasty-shy [4]

Answer:

1) Randomization: We assume that we have a random sample of students

2) 10% condition, for this case we assume that the sample size is lower than 10% of the real population size

3) np = 500*0.66= 330 >10

n(1-p) = 500*(1-0.66) =170>10

So then we can use the normal approximation for the distribution of p, since the conditions are satisfied

The population proportion have the following distribution :

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

And we have :

\mu_p = 0.66

\sigma_{p}= \sqrt{\frac{0.66(1-0.66)}{500}}= 0.0212

Using the 68-95-99.7% rule we expect 68% of the values between 0.639 (63.9%) and 0.681 (68.1%), 95% of the values between 0.618(61.8%) and 0.702(70.2%) and 99.7% of the values between 0.596(59.6%) and 0.724(72.4%).

Step-by-step explanation:

For this case we know that we have a sample of n = 500 students and we have a percentage of expected return for their sophomore years given 66% and on fraction would be 0.66 and we are interested on the distribution for the population proportion p.

We want to know if we can apply the normal approximation, so we need to check 3 conditions:

1) Randomization: We assume that we have a random sample of students

2) 10% condition, for this case we assume that the sample size is lower than 10% of the real population size

3) np = 500*0.66= 330 >10

n(1-p) = 500*(1-0.66) =170>10

So then we can use the normal approximation for the distribution of p, since the conditions are satisfied

The population proportion have the following distribution :

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

And we have :

\mu_p = 0.66

\sigma_{p}= \sqrt{\frac{0.66(1-0.66)}{500}}= 0.0212

And we can use the empirical rule to describe the distribution of percentages.

The empirical rule, also known as three-sigma rule or 68-95-99.7 rule, "is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ)".

On this case in order to check if the random variable X follows a normal distribution we can use the empirical rule that states the following:

• The probability of obtain values within one deviation from the mean is 0.68

• The probability of obtain values within two deviation's from the mean is 0.95

• The probability of obtain values within three deviation's from the mean is 0.997

Using the 68-95-99.7% rule we expect 68% of the values between 0.639 (63.9%) and 0.681 (68.1%), 95% of the values between 0.618(61.8%) and 0.702(70.2%) and 99.7% of the values between 0.596(59.6%) and 0.724(72.4%).

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Latitia had 12 marbles. After she gave 2 marbles to Amelia she has 10/12 of her marbles left. What fraction of the marbles did l
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Answer:

The answer here would be 1/6.

Step-by-step explanation:

If Amelia originally has 12 marbles (12/12), then gives away 2, she then has 10 marbles (10/12). This means she gave away 2 of the 12 marbles she has (2/12). This fraction can then be reduced to 1/6 by dividing the denominator and numerator by 2.

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3 years ago
Please give me the answer and why
masha68 [24]

Answer:

1 black

Step-by-step explanation:

one more black to reach 3:2

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