Question

Find the point of the intersection for the given systems y=x^2+1 and y=x+1

Answer 1

set them equal to each other

x²+1=x+1

minus 1 from both sides

x²=x

minus x both sides

x²-x=0

factor

x(x-1)=0

set each to 0

x=0

x-1=0

x=1

subsitute back to find y values

y=x+1, y=0+1, y=1, one point is (0,1)

y=x+1, y=1+1, y=2, another point is (1,2)

the 2 points of intersection are (0,1) and (1,2)