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trasher [3.6K]
3 years ago
6

The vertex of this angle is​

Mathematics
2 answers:
Allushta [10]3 years ago
6 0

S

i need to make this 20 characters

otez555 [7]3 years ago
3 0

Answer:

s a vertex is a corner so s

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25 POINTS -4(x+2) Plz help asap
timofeeve [1]

Answer:

- 4x - 8

Step-by-step explanation:

- 4(x + 2) =  - 4x - 8

Hope this helps ;) ❤❤❤

7 0
3 years ago
Read 2 more answers
Let f (x) = 2x - 1, g(x) = 3x, and h(x) = x2 + 1. Compute the following: h (h(x)) and. g (h (x))
ki77a [65]
H(h(x)) means to use the entire function h(x) as the x value in the function h(x)..

h(h(x)) = (x²+1)² + 1
= (x²+1)(x²+1) + 1
= (x^4 + x² + x² + 1) + 1 
= x^4 + 2x² + 2

g(h(x)) means to use the entire function h(x) as the x value in the function g(x)..

g(h(x)) = 3(x² + 1)
= 3x² + 3
g(h(x))
7 0
2 years ago
How many times can 4 go into 36
hammer [34]
It's very easy... just do 36/4.
36/4= 9.
4 0
2 years ago
Read 2 more answers
Use the Distributive Property on 45x-6
Alexandra [31]

Answer:

<h3>180</h3>

Step-by-step explanation:

<h3>45 × -6 = 45 × [10+(-6)]</h3><h3>45 × (10-6)</h3><h3>45 × 4</h3><h3>180</h3>
5 0
3 years ago
Consider the probability that greater than 96 out of 153 DVDs will work correctly. Assume the probability that a given DVD will
ICE Princess25 [194]

Answer:

0.3594 = 35.94% probability that greater than 96 out of 153 DVDs will work correctly.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 153, p = 0.62

So

\mu = E(X) = np = 153*0.62 = 94.86

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{153*0.62*0.38} = 6

Probability that greater than 96 out of 153 DVDs will work correctly.

97 or more DVDs, which is 1 subtracted by the pvalue of Z when X = 97. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{97 - 94.86}{6}

Z = 0.36

Z = 0.36 has a pvalue of 0.6406

1 - 0.6406 = 0.3594

0.3594 = 35.94% probability that greater than 96 out of 153 DVDs will work correctly.

3 0
3 years ago
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