All categories

3 years ago

The graph shows a journey in a car Help Fast!!!

Mathematics

1 answer:

Sever21 [200]3 years ago

3 0

Answer: i think the answer would be c

i hope this helps you out!

Step-by-step explanation:

You might be interested in

Which of the following is a nonlinear function

pogonyaev

Answer:

Linear functions are equations where the greatest power of the variable (typically x) is 1;

They are graphed as straight lines;

So, any function that has the following format:

f(x) = ax + b;

Nonlinear functions would be any equation that has a variable to a power greater than 1;

This could be a quadratic equation or an exponential equation

6 0

1 year ago

What is the solution to the equation x/3+x/6=7/2

Alchen [17]

Answer:

x = y

Step-by-step explanation:

x/3 + x/6 = 7/2

2x + x = 21

3x = 21

(divide 3 on both sides)

x = 7

5 0

2 years ago

Nickel uses 5 ounces of mushrooms 2 ounces of butter and 1/4 pint of cream to make mushroom soup find the ratio of the number of

Zigmanuir [339]

1/4 of a pint is 4 oz. so the ratio ofmushrooms to butter to cream would be 5:2:4.

5 0

2 years ago

On a coordinate plane, rhombus W X Y Z is shown. Point W is at (7, 2), point X is at (5, negative 1), point Y is at (3, 2), and

Otrada [13]

Answer:

$P = 4\sqrt{13}$

Step-by-step explanation:

Given

$W = (7, 2)$

$X = (5, -1)$

$Y = (3, 2)$

$Z =(5, 5)$

Required

The perimeter

To do this, we first calculate the side lengths using distance formula

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2$

So, we have:

$WX = \sqrt{(5- 7)^2 + (-1 - 2)^2$

$WX = \sqrt{13}$

$XY = \sqrt{(3-5)^2 + (2--1)^2}$

$XY = \sqrt{13}$

$YZ = \sqrt{(5-3)^2 + (5-2)^2}$

$YZ = \sqrt{13}$

$ZW = \sqrt{(7 - 5)^2 + (2 - 5)^2}$

$ZW = \sqrt{13}$

The perimeter is:

$P = WX + XY + YZ + ZW$

$P = \sqrt{13}+\sqrt{13}+\sqrt{13}+\sqrt{13}$

$P = 4\sqrt{13}$

5 0

3 years ago

Read 2 more answers

What is the slope for y=0.5x+10

laila [671]

Answer: the answer is 0.5

Step-by-step explanation:

Y=mx+b mx= slope b= y intercept

5 0

2 years ago