<u>Part a)</u> if a page is reduced to 80%, what percent enlargement is needed to return it to its original size?
Let
x---------> the percent enlargement
we know that
the original size is the 100%
so
x*80%=100%
x=(100%/80%)
x=1.25--------> 1.25=(125/100)=125%
therefore
<u>the answer Part a) is</u>
the percent enlargement is 125%
<u>Part b)</u> Estimate the number of times in succession that a page must be copied to make the final copy less than 15% of the size of the original
we know that
A photocopy machine can reduce copies to 80% of their original size
so
Copy N 1
0.80*100%=80%
Copy N 2
0.80*80%=64%
Copy N 3
0.80*64%=51.2%
Copy N 4
0.80*51.2%=40.96%
Copy N 5
0.80*40.96%=32.77%
Copy N 6
0.80*32.77%=26.21%
Copy N 7
0.80*26.21%=20.97%
Copy N 8
0.80*20.97%=16.78%
Copy N 9
0.80*16.78%=13.42%-------------> 13.42% < 15%
therefore
<u>the answer Part b) is</u>
the number of times in succession is 9
Answer:Once you have the value of a variable you can check by plugging it into the equation and seeing if it’s right or not
Step-by-step explanation:
Answer:828.96m^2
Step-by-step explanation:
radius(r)=8m
L=25m
π=3.14
total surface area of cone(tsa)=πxr^2+πxrxL
Tsa=3.14x8^2+3.14x8x25
Tsa=3.14x8x8+3.14x8x25
Tsa=200.96 + 628
Tsa=828.96
Answer:
47 rows
Step-by-step explanation:
To find the amount of needed rows, we will use the math operation division. We will take the total and divide it by the amount in each row.
846/18=47
To seat 18 people in each row, you will need 47 rows.
