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kkurt [141]
3 years ago
8

Which number can be classified as a terminating decimal number?

Mathematics
1 answer:
seropon [69]3 years ago
3 0
0.1257 is a terminating decimap
You might be interested in
3x+2y=3<br><br>2x+3y=2 <br><br>solve for x
kicyunya [14]

Answer:

1: x=1 - 2y/3 2: x= 1 - 3y/2

Hope this helped you out!

8 0
3 years ago
Given a circle in the complex plane with a diameter that has endpoints at: -12 − i and 18 + 15i Find the center of the circle. +
azamat

Answer: The center of the circle is 3+7i

Explanation: Let z1 and z1 be the two end points and c be the center to be determined. The center lies half of the difference between z1 and z1, measured from z1:

z_1=-12-i\\z_2=18+15i\\c=z_1+\frac{z_2-z_1}{2}=-12-i +15+8i=3+7i

4 0
3 years ago
Read 2 more answers
Somebody please help
Phantasy [73]

Answer:

ln;cjh

Step-by-step explanation:

cJZfhlanssfiusdfhjkhuhajkhj kh lkjjljf;lakjsdlfkasld j lij lkflaksdfd ljilkjljijdfasdfj

3 0
3 years ago
The mean weight of an adult is 69 kilograms with a variance of 121. If 31 adults are randomly selected, what is the probability
amid [387]

Answer:

0.2236 = 22.36% probability that the sample mean would be greater than 70.5 kilograms.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Also, important to remember that the standard deviation is the square root of the variance.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 69, \sigma = \sqrt{121} = 11, n = 31, s = \frac{11}{\sqrt{31}} = 1.97565

What is the probability that the sample mean would be greater than 70.5 kilograms?

This is 1 subtracted by the pvalue of Z when X = 70.5. So

Z = \frac{X - \mu}{\sigma}

By the Central limit theorem

Z = \frac{X - \mu}{s}

Z = \frac{70.5 - 69}{1.97565}

Z = 0.76

Z = 0.76 has a pvalue of 0.7764

1 - 0.7764 = 0.2236

0.2236 = 22.36% probability that the sample mean would be greater than 70.5 kilograms.

8 0
3 years ago
Mr.Montgomery's class, there are 8 boys and 12 girls.If Mr.Montgomery selects 1 student from his class at random, what is the pr
Gnoma [55]
Probability=number of specific outcomes / total possible outcomes

P(g)=12/(12+8)

P(g)=12/20

P(g)=3/5
7 0
3 years ago
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