Answer:
No the facility dose not have the same pattern as the recent report at the 10% level
Step-by-step explanation:
To determine if the Facility have the same pattern ; Perform Chi squared test for Goodness of fit
state the hypothesis
H0 : μ = same pattern
Ha : μ ≠ same pattern
expected frequency ( E ) = proportion * summation of frequency
summation of frequency = 1000
degree of freedom = 7 - 1 = 6
<u>Next : Calculate the expected frequency (E) , (O-E)²/E. given that the observed frequency and expected proportion is given </u>
<u>For Monday</u>
expected frequency = proportion * frequency = 0.1 * 1000 = 100
(O-E)²/E. = ( 120 - 100 )^2 / 100 = 4.0.
observed frequency ( O ) , expected frequency ( E )
<u>For Tuesday </u>
E = 0.1 * 1000 = 100
(O-E)²/E = ( 130 - 100 )^2 / 100 = 9.0
<em>Repeat same calculations for Wednesday through Sunday </em>
Then perform Chi-squared test
X² = Σ(O-E)²/E = 63.642
∝ = 0.1
df = 6
hence P-value = 0.000 ( =chisq.dist.rt(test-stat,df)
since P-value < ∝ ; we will fail to reject Ha hence we reject H0
